Solve 10 × (480 – 80) + 144 ÷ (3 + 3)2 = ?
2023
Solve 10 × (480 – 80) + 144 ÷ (3 + 3)2 = ?
- A.
4422
- B.
4400
- C.
4004
- D.
None of the above
Show answer & explanation
Correct answer: C

Concept: The order of operations (BODMAS/PEMDAS) fixes a strict evaluation sequence for a mixed expression — first resolve every Bracket, then evaluate any Order/Exponent, then perform Division and Multiplication (left to right), and only then Addition and Subtraction (left to right). Skipping or reordering any stage changes the result.
Resolve the brackets first: (480 − 80) = 400, and (3 + 3) = 6.
Apply the exponent to the resolved bracket: 62 = 36.
Perform multiplication and division, left to right: 10 × 400 = 4000, and 144 ÷ 36 = 4.
Finally perform the addition: 4000 + 4 = 4004.
Cross-check: 36 × 4 = 144, confirming 144 ÷ 36 = 4 exactly, and 10 × 400 is an exact integer multiple with no remainder — so the two terms combine cleanly to 4000 + 4 = 4004, with no rounding or leftover fraction anywhere in the computation.
The expression evaluates to 4004.