Solve 10 × (480 – 80) + 144 ÷ (3 + 3)2 = ?

2023

Solve 10 × (480 – 80) + 144 ÷ (3 + 3)2 = ?

  1. A.

    4422

  2. B.

    4400

  3. C.

    4004

  4. D.

    None of the above

Show answer & explanation

Correct answer: C

Concept: The order of operations (BODMAS/PEMDAS) fixes a strict evaluation sequence for a mixed expression — first resolve every Bracket, then evaluate any Order/Exponent, then perform Division and Multiplication (left to right), and only then Addition and Subtraction (left to right). Skipping or reordering any stage changes the result.

  1. Resolve the brackets first: (480 − 80) = 400, and (3 + 3) = 6.

  2. Apply the exponent to the resolved bracket: 62 = 36.

  3. Perform multiplication and division, left to right: 10 × 400 = 4000, and 144 ÷ 36 = 4.

  4. Finally perform the addition: 4000 + 4 = 4004.

Cross-check: 36 × 4 = 144, confirming 144 ÷ 36 = 4 exactly, and 10 × 400 is an exact integer multiple with no remainder — so the two terms combine cleanly to 4000 + 4 = 4004, with no rounding or leftover fraction anywhere in the computation.

The expression evaluates to 4004.

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