Manish got married 12 years ago. His present age is 1.5 times his age at the…
2025
Manish got married 12 years ago. His present age is 1.5 times his age at the time of his marriage. Manish’s brother was 8 years younger to him at the time of his marriage. The age of Manish’s brother is:
- A.
22 years
- B.
26 years
- C.
28 years
- D.
30 years
Attempted by 3 students.
Show answer & explanation
Correct answer: C
In age problems that combine a ratio condition with a fixed reference time (such as marriage) and a sibling's age gap, express every unknown age from ONE reference point, turn each ratio or difference statement into a linear equation, and only then shift the result to the time point actually asked about.
Let Manish's age at the time of his marriage (12 years ago) be x years.
His present age is 12 years after the marriage, so present age = x + 12.
The present age is 1.5 times the age at marriage: x + 12 = 1.5x.
Solving: 12 = 1.5x − x = 0.5x, so x = 24. Manish's age at the time of marriage was 24 years, making his present age 36 years.
Manish's brother was 8 years younger than Manish at the time of the marriage, so the brother's age at marriage = 24 − 8 = 16 years.
The same 12 years have passed for the brother too, so his present age = 16 + 12 = 28 years.
Check: 1.5 × 24 = 36, which matches Manish's present age. Also, the 8-year gap between the brothers stays constant over time, so 36 − 8 = 28 gives the same present age for the brother — confirming 28 years.
