To finish a piece of work, P takes five times as long as Q, and six times as…
2025
To finish a piece of work, P takes five times as long as Q, and six times as long as R. Working together, they can finish the work in 4 days. In how many days can Q alone complete the work?
- A.
48/5
- B.
8
- C.
48
- D.
12/5
Show answer & explanation
Correct answer: A
Work-rate principle: if a person completes a task alone in D days, their work rate is 1/D of the task per day. When several people work together, their combined work rate is the sum of their individual rates, and the time they take together equals 1 divided by that combined rate.
Let the number of days Q takes to finish the work alone be x.
Since P takes five times as long as Q, P's time alone is 5x days.
Since P takes six times as long as R, R's time alone is P's time divided by 6, i.e. 5x/6 days.
Individual work rates: P's rate = 1/(5x), Q's rate = 1/x, R's rate = 6/(5x).
Combined rate = 1/(5x) + 1/x + 6/(5x) = (1 + 5 + 6)/(5x) = 12/(5x).
Since together they finish the work in 4 days, the combined rate must equal 1/4.
Setting 12/(5x) = 1/4 gives 5x = 48, so x = 48/5.
Cross-check: with x = 48/5, Q's rate = 5/48, P's time = 5x = 48 days (rate 1/48), and R's time = 5x/6 = 8 days (rate 6/48). Combined rate = 5/48 + 1/48 + 6/48 = 12/48 = 1/4, matching the given combined time of 4 days.
Therefore, Q alone can complete the work in 48/5 days (9.6 days).