Two trains for Y leave X at 6.30am and 7.40am and travel at 30km/hr and 40…

Answer: 140

Let t be the time in hours after 6:30 when the two trains meet.

• Distance travelled by the first (slower) train = 30 × t km.

• The second (faster) train starts at 7:40, which is 1 hour 10 minutes = 7/6 hours after 6:30, so its travel time is t − 7/6 hours.

• Distance travelled by the faster train = 40 × (t − 7/6) km.

• Set distances equal because they meet at the same point: 30t = 40(t − 7/6).

• Solve: 30t = 40t − 40 × 7/6 = 40t − 140/3 ⇒ 10t = 140/3 ⇒ t = 14/3 hours = 4 hours 40 minutes.

• Distance from X = 30 × t = 30 × 14/3 = 140 km.