Using the digits 1,5,2,8 four digit numbers are formed. The sum of all…

Answer: 106656

Reason:

• There are 4 distinct digits (1, 5, 2, 8). The total number of 4-digit permutations is 4! = 24, and each digit appears in each place (thousands, hundreds, tens, units) exactly (4-1)! = 3! = 6 times.

• Sum of the digits = 1 + 5 + 2 + 8 = 16.

• Contribution per place = (sum of digits) * (3!) = 16 * 6 = 96. There are four place values with weights 1000, 100, 10, 1, so total place-weight factor = 1000 + 100 + 10 + 1 = 1111.

• Total sum = 96 * 1111 = 106656.

Therefore, the sum of all 4-digit numbers formed using 1, 5, 2, 8 (without repetition) is 106656.