If 3^(x+1) = 5^(x-2), then find the value of x. (Take log 5 = 0.6989 and log 3…
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If 3^(x+1) = 5^(x-2), then find the value of x.
(Take log 5 = 0.6989 and log 3 = 0.4771)
- A.
5
- B.
7.5
- C.
11
- D.
8.5
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Correct answer: D
Solution: Solve the equation 3^(x+1) = 5^(x-2) by taking logarithms.
Take logarithm of both sides: (x + 1) log 3 = (x - 2) log 5.
Expand: x log 3 + log 3 = x log 5 - 2 log 5.
Collect x terms: x (log 3 - log 5) = -2 log 5 - log 3.
Solve for x: x = (2 log 5 + log 3) / (log 5 - log 3).
Substitute the given values: numerator = 2 × 0.6989 + 0.4771 = 1.8749; denominator = 0.6989 - 0.4771 = 0.2218.
Compute: x = 1.8749 / 0.2218 ≈ 8.45, which rounds to 8.5.