Anaya is 15m to the west of Rithika. Rithika is 20m to the north of Genelia.…

Concept: The shortest path between two points reached by moving along perpendicular directions (north-south and east-west) is the straight-line diagonal of a right triangle whose legs are the net east-west and north-south displacements between the points, found using the Pythagorean theorem: distance = √(dx2 + dy2)

Application: Assign coordinates step by step and compute each straight-line leg:

1. Fix a coordinate grid with east as the positive x-direction and north as the positive y-direction, and place Genelia at the origin (0, 0).

2. Rithika is 20m north of Genelia, so Rithika is at (0, 20).

3. Anaya is 15m west of Rithika, so Anaya is at (-15, 20).

4. Genelia is 12m east of Diksha, so Diksha is at (-12, 0).

5. Faizah is 16m north of Diksha, so Faizah is at (-12, 16).

6. Anaya to Faizah: the horizontal gap is 15 - 12 = 3m and the vertical gap is 20 - 16 = 4m, so the shortest distance is √(32 + 42) = √25 = 5m.

7. Faizah to Genelia: the horizontal gap is 12m and the vertical gap is 16m, so the shortest distance is √(122 + 162) = √400 = 20m.

8. Total distance travelled by Anaya = 5m + 20m = 25m.

Cross-check: Placing the origin at Diksha instead gives the same result: Diksha (0, 0), Genelia (12, 0), Faizah (0, 16), Rithika (12, 20), Anaya (-3, 20). The Anaya-Faizah gap is still 3m and 4m (distance 5m), and the Faizah-Genelia gap is still 12m and 16m (distance 20m) — the 25m total does not depend on which point is chosen as the origin.

Answer: The total distance travelled by Anaya is 25m.