The output of the following ‘C’ language code is:
void main()
{
int x=1, i, y=2;
for(i=0;i<10;i++)
{
x << 1;
y=x+i;
}
printf("%0d,%0d",x,y);
}

Question

The output of the following ‘C’ language code is: void main() { int x=1, i, y=2; for(i=0;i<10;i++) { x << 1; y=x+i; } printf("%0d,%0d",x,y); }

Accepted Answer

Correct answer: D — The code initializes x = 1 and y = 2. Inside the loop, the expression x << 1; shifts bits left but does not assign the value back to x (it lacks =). Thus, x remains 1 throughout. In the final iteration (i = 9), y = x + i becomes 1 + 9 = 10. Output: 1,10 (Option D).

Answer

A. 10,11

Answer

B. 1,1

Answer

C. 10,1

Answer

D. 1,10

The output of the following ‘C’ language code is: void main() { int x=1, i,…