Simplify the Boolean expression A'C(A'BD)' + A'BC'D' + AB'C:

2017

Answer: A. B'C+A'D'(B+C) — Using Boolean simplification, A'C(A'BD)' + A'BC'D' + AB'C reduces to B'C + A'D'(B + C).

1. A.

   B'C+A'D'(B+C)

2. B.

   AD'(C+B)+ BC'

3. C.

   ABC'

4. D.

   1

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