A puppy was trying to find its mother. It was facing east and walked for 10…
2025
A puppy was trying to find its mother. It was facing east and walked for 10 mt. It turned south then and walked another 10 mt. Then it started walking towards North it walked for 20 mt and turned west. It walked 10 mt. and moved south for 2 mt. In which direction is it from the original position and how far?
Answer: C. 8 mt north — Concept: Model direction-sense (distance and direction) problems on a coordinate plane — take East as the positive x-axis and North as the positive y-axis,…
- A.
60 mt north-east
- B.
10 m north-east
- C.
8 mt north
- D.
can't be determined
Show answer & explanation
Correct answer: C
Concept: Model direction-sense (distance and direction) problems on a coordinate plane — take East as the positive x-axis and North as the positive y-axis, starting from the origin. Every straight walk changes only one coordinate; each turn fixes which axis the next walk affects. The final answer is the straight-line displacement (magnitude and direction) from the origin to the finishing point, not the total distance walked.
Application:
Start at the origin (0, 0), facing East.
Walk 10 m East: position becomes (10, 0).
Turn South and walk 10 m: the y-coordinate falls by 10, giving (10, -10).
Turn North and walk 20 m: the y-coordinate rises by 20 from -10, giving (10, 10).
Turn West and walk 10 m: the x-coordinate falls by 10, giving (0, 10).
Turn South and walk 2 m: the y-coordinate falls by 2, giving (0, 8).
Cross-check:
Net east-west displacement across the two east/west legs: 10 m east - 10 m west = 0. Net north-south displacement across the three north/south legs: -10 + 20 - 2 = 8 m north. Both methods agree with the coordinate walk: the finishing point (0, 8) sits directly on the positive y-axis, so the straight-line distance is √(02 + 82) = √64 = 8 m.
The puppy ends up 8 m north of its original position.