The famous church in the city of Kumbakonnam has a big clock tower and is said…

Concept: When a clock runs at a constant faulty rate — gaining or losing a fixed number of minutes every real hour — the time it displays and the true elapsed real time are related by a constant ratio. The real elapsed time equals the clock's displayed elapsed time multiplied by (60 minutes ÷ minutes the faulty clock actually advances per real hour); because this ratio never changes, it applies uniformly no matter how long the elapsed span is.

Application:

1. Find the duration the faulty clock itself displays, from Monday 10:00 AM to Friday 3:00 PM: Monday 10 AM to Friday 10 AM is 4 days = 96 hours, plus 5 more hours to 3 PM, giving a displayed duration of 101 hours.

2. Fix the conversion ratio: the clock loses 6 minutes every real hour, so it advances only 54 minutes for every 60 real minutes — 54 faulty minutes = 60 real minutes.

3. Convert the 101-hour (6060-minute) displayed duration to real time: real minutes = 6060 × 60/54 = 6733.33 minutes = 112 hours 13 minutes 20 seconds.

4. Add this real duration to the start point: Monday 10:00 AM + 96 hours lands on Friday 10:00 AM; the remaining 16 hours 13 minutes 20 seconds takes it to Saturday 2:13:20 AM — the actual time.

Cross-check: Solving directly confirms the same value: if R is the real hours elapsed, the faulty clock shows 0.9R hours (since it runs at 54/60 = 0.9 of real speed). Setting 0.9R = 101 gives R = 112.22 hours, the same real duration found above — the conversion is consistent.

Result: None of the three specific clock-times listed match Saturday 2:13 AM, so the correct choice is the 'none' option.