Which of the following series observes the rule, "Skip in between adjacent…
2015
Which of the following series observes the rule, "Skip in between adjacent letters, increasing one letter more each time to build a set of letters"?
- A.
ACFILQ
- B.
BDGKPV
- C.
CEHLQV
- D.
HILPUZ
- E.
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Correct answer: B
CONCEPT: In an alphabet series governed by an "increasing skip" rule, if the sequence skips 1 letter between the first pair of terms, 2 letters between the second pair, 3 letters between the third pair, and so on, the positional gap (difference in alphabet rank) between consecutive letters must rise by exactly one, step after step. Skipping s letters between two terms means their positional gap is s + 1.
The rule starts by skipping 1 letter between the first pair, so for a 6-letter series the five required positional gaps, in order, are 2, 3, 4, 5, 6.
Assign alphabet ranks: B = 2, D = 4, G = 7, K = 11, P = 16, V = 22.
B to D: gap 4 - 2 = 2, skipping only C - matches the required first gap of 2 (skip of 1 letter).
D to G: gap 7 - 4 = 3, skipping E and F - matches the required second gap of 3 (skip of 2 letters).
G to K: gap 11 - 7 = 4, skipping H, I and J - matches the required third gap of 4 (skip of 3 letters).
K to P: gap 16 - 11 = 5, skipping L, M, N and O - matches the required fourth gap of 5 (skip of 4 letters).
P to V: gap 22 - 16 = 6, skipping Q, R, S, T and U - matches the required fifth gap of 6 (skip of 5 letters).
CROSS-CHECK: comparing the positional gap sequence of every lettered option shows only one sustains the increasing pattern through all five gaps without a break.
Lettered sequence | Gap sequence | Where the pattern holds |
|---|---|---|
A C F I L Q | 2, 3, 3, 3, 5 | breaks after the 2nd gap (stalls at a skip of 2 instead of rising to 3) |
B D G K P V | 2, 3, 4, 5, 6 | holds through all five gaps without interruption |
C E H L Q V | 2, 3, 4, 5, 5 | breaks at the final gap (stays at a skip of 4 instead of rising to 5) |
H I L P U Z | 1, 3, 4, 5, 5 | breaks at the very first gap (adjacent letters - a skip of 0, not 1) |
Since B D G K P V is the only sequence whose gaps rise steadily as 2, 3, 4, 5, 6 across every step, it is the series that satisfies the stated rule.