6 persons are sitting in two rows, numbered 3–3. E does not sit at any of the…
2025
6 persons are sitting in two rows, numbered 3–3. E does not sit at any of the ends. D is second to the left of F. C is neighbour of E and sits diagonally opposite to D. B is neighbour of F. Then who will be in front of B?
- A.
A
- B.
E
- C.
C
- D.
D
Attempted by 6 students.
Show answer & explanation
Correct answer: B
Concept: In a two-row-of-three seating puzzle, seats in the two facing rows line up seat-for-seat — each seat has exactly one seat directly opposite it in the other row (same column), while a person's same-row companions on either side are their neighbours. A clue such as ‘X is second to the left of Y’ places X and Y in the same row at its two end seats, since the middle seat is only one step from either end.
Working it out:
“D is second to the left of F” places D and F at the two end seats of one row — D on the left end, F on the right end.
“B is neighbour of F”: since F sits at an end, F’s only same-row neighbour is the middle seat of its own row — so B fills that middle seat, giving the row order D – B – F.
“E does not sit at any end of any row”: with the D–B–F row now fully occupied, E cannot be in that row at all, so E must take the middle seat of the other row — its only non-end seat.
“C is neighbour of E” places C at one of the two end seats of E’s row (both are next to E’s middle seat); “C sits diagonally opposite to D” (D being at the left end of the D–B–F row) rules out the end seat that would face D directly, so C takes the far end, leaving the last seat for A. That row reads A – E – C.
With D – B – F facing A – E – C seat-for-seat, the seat directly in front of B (the row’s middle seat) is E’s seat.
Final layout:
Row | Left end | Middle | Right end |
|---|---|---|---|
Row 1 (D–F row) | D | B | F |
Row 2 (facing row) | A | E | C |
Cross-check: D and F are the two ends of one row, two seats apart; E sits in a middle seat, not an end; C is adjacent to E and does not directly face D; B is adjacent to F. Every condition holds, confirming E is in front of B.