Addendo Property & Equivalent Ratio Property

Duration: 16 min

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This lesson on Ratio and Proportion, presented by Yash Jain, focuses on two key algebraic properties: the Addendo Property and the Equivalent Ratio Property. The video begins by defining a ratio as a comparison of two quantities before introducing the Addendo Property, which states that if multiple ratios are equal (a/b = c/d = e/f), their common value is preserved when the sums of their antecedents and consequents are taken. This is demonstrated numerically using 2/3 = 6/9 = 8/12, where (2+6+8)/(3+9+12) simplifies to 16/24, which reduces back to 2/3. The instructor then provides a formal algebraic proof by setting the equal ratios to a constant k, expressing numerators as multiples of denominators (a=bk, c=dk), and showing that the combined fraction simplifies to k. A generalized version using variables p, q, r, s, t, u is also presented to show that multiplying terms by constants maintains equivalence. The lesson applies the Addendo Property to solve a problem where p:q = r:s = t:u = 2:3, finding (p+r+t)/(q+s+u) to be 2/3. The second half introduces the Equivalent Ratio Property, which states that if a:b :: c:d, then (a±c):(b±d) :: a:b. This is proven by setting a/b = c/d = k and showing that (a+c)/(b+d) simplifies to k. The property is extended to forms like (pa+qc)/(pb+qd). A final problem asks for the value of (ab+cd)/(b²+d²) given a:b = c:d = 2:3, which is solved by recognizing the expression as an application of the Equivalent Ratio Property with p=b and q=d, yielding 2/3. The lesson concludes with a thank-you slide.

Chapters

  1. 0:00 2:00 00:00-02:00

    The lesson opens with a title slide for Ratio and Proportion, defining ratio as the comparison of two quantities. The instructor introduces the Addendo Property with the rule: if a:b = c:d = e:f, then each ratio equals (a+c+e):(b+d+f). A numerical example using 2/3 = 6/9 = 8/12 is shown, where (2+6+8)/(3+9+12) = 16/24 simplifies to 2/3. Red annotations highlight corresponding terms and circle the final combined fraction, reinforcing the visual connection between individual ratios and their sum.

  2. 2:00 5:00 02:00-05:00

    The instructor transitions from the numerical example to a formal algebraic proof of the Addendo Property. By setting a/b = c/d = e/f = k, the numerators are expressed as multiples of denominators: a=bk, c=dk, e=fk. Substituting these into (a+c+e)/(b+d+f) yields (bk+dk+fk)/(b+d+f), which factors to k(b+d+f)/(b+d+f) and cancels to k. This proves that the combined fraction equals the original ratio, establishing the extended proportion a/b = c/d = e/f = (a+c+e)/(b+d+f).

  3. 5:00 10:00 05:00-10:00

    The proof is generalized using new variables p, q, r, s, t, u to represent terms in equivalent fractions ma/mb, nc/nd, oe/of. The combined fraction (p+r+t)/(q+s+u) is shown to equal (ma+nc+oe)/(mb+nd+of), confirming that multiplying terms by constants preserves the ratio. The Addendo Property is then applied to a problem: if p:q = r:s = t:u = 2:3, then (p+r+t)/(q+s+u) = 2/3. The lesson transitions to the Equivalent Ratio Property, stating that if a:b :: c:d, then (a±c):(b±d) :: a:b.

  4. 10:00 15:00 10:00-15:00

    The Equivalent Ratio Property is proven by setting a/b = c/d = k (k ≠ 0) and showing that (a+c)/(b+d) simplifies to k(b+d)/(b+d) = k. The property is extended algebraically to forms like (pa+qc)/(pb+qd). A problem on an orange slide asks: if a:b = c:d = 2:3, what is (ab+cd)/(b²+d²)? The instructor re-expresses the target fraction as (ba+dc)/(bb+dd), identifying it with p=b and q=d, so the value is 2/3 by the Equivalent Ratio Property.

  5. 15:00 15:45 15:00-15:45

    The lesson concludes with a white slide headed 'Equivalent Ratio Property' that recaps two examples, boxing (ab+cd)/(b²+d²) and ending with a generalized form (4a-3c+9e)/(4b-3d+9f). A final 'THANKS FOR WATCHING' slide closes the video, signaling the end of the instructional content on ratio properties.

The lesson systematically builds from concrete examples to abstract proofs, a pedagogical approach that helps students internalize ratio properties. The Addendo Property is first demonstrated numerically, then proven algebraically using a constant k, and finally generalized with additional variables. This three-step progression (example → proof → generalization) is a key teaching pattern worth noting for exam preparation. The Equivalent Ratio Property follows a similar structure, with the proof emphasizing that (a±c)/(b±d) preserves the common ratio k. The final problem on (ab+cd)/(b²+d²) is particularly instructive because it requires recognizing that the expression fits the (pa+qc)/(pb+qd) form with p=b and q=d, a non-obvious substitution that tests conceptual understanding rather than rote application. Students should focus on identifying when a given fraction can be rewritten to match the property's standard form, as this is the core skill being assessed.

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