Due to reduction in the price of tea leaves of a particular brand by 8%, Ajay…

Concept: If a shopper spends the same total money M both before and after a price cut, and the price falls by a fraction r, then the extra quantity bought after the cut, valued at the NEW (reduced) price, is exactly equal to r × M. In symbols: r × M = (extra quantity) × (reduced price).

Applying this to the given values (r = 8% = 0.08, M = ₹460, extra quantity = 125 g = 0.125 kg, reduced price per kg = P):

1. Write the identity with the known values: r × M = (extra quantity) × P, i.e. 0.08 × 460 = 0.125 × P.

2. Evaluate the left-hand side: 0.08 × 460 = 36.8, so 36.8 = 0.125 × P.

3. Solve for P: P = 36.8 ÷ 0.125 = 294.4.

4. Therefore the reduced price per kilogram is ₹294.40.

Cross-check independently by reconstructing the original price and both quantities bought:

1. A reduced price of ₹294.40 is 92% of the original price (since the cut is 8%), so the original price per kg = 294.40 ÷ 0.92 = ₹320.

2. Quantity bought for ₹460 at the original price: 460 ÷ 320 = 1.4375 kg = 1437.5 g.

3. Quantity bought for ₹460 at the reduced price: 460 ÷ 294.40 = 1.5625 kg = 1562.5 g.

4. Difference in quantity: 1562.5 g − 1437.5 g = 125 g, which matches the extra quantity given in the question — confirming the reduced price.

Hence, the reduced price of tea leaves per kg is ₹294.40.