One year ago the ratio between Samir and Ashok's age was 4 : 3. One year hence…
2015
One year ago the ratio between Samir and Ashok's age was 4 : 3. One year hence the ratio of their age will be 5 : 4. What is the sum of their present ages in years?
Answer: C. 16 years — Let Samir's age one year ago be 4x years and Ashok's age one year ago be 3x years. Therefore, their present ages are (4x + 1) and (3x + 1) years respectively.…
- A.
12 years
- B.
15 years
- C.
16 years
- D.
Cannot be determined
- E.
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Correct answer: C
Let Samir's age one year ago be 4x years and Ashok's age one year ago be 3x years.
Therefore, their present ages are (4x + 1) and (3x + 1) years respectively.
One year hence, their ages will be (4x + 2) and (3x + 2) years.
According to the problem, the ratio of their ages one year hence will be 5 : 4.
So, (4x + 2) / (3x + 2) = 5 / 4.
Cross-multiplying: 4(4x + 2) = 5(3x + 2)
16x + 8 = 15x + 10
Solving: 16x - 15x = 10 - 8 → x = 2
Now, present ages: Samir = 4x + 1 = 4(2) + 1 = 9 years, Ashok = 3x + 1 = 3(2) + 1 = 7 years.
Sum of their present ages = 9 + 7 = 16 years.
हिन्दी उत्तर:
माना एक वर्ष पूर्व समीर की आयु 4x वर्ष थी और अशोक की आयु 3x वर्ष थी।
इसलिए, वर्तमान आयु (4x + 1) और (3x + 1) वर्ष है।
एक वर्ष बाद आयु (4x + 2) और (3x + 2) वर्ष होगी।
प्रश्नानुसार, एक वर्ष बाद उनकी आयु का अनुपात 5 : 4 होगा।
इसलिए, (4x + 2) / (3x + 2) = 5 / 4।
क्रॉस-गुणा करने पर: 4(4x + 2) = 5(3x + 2)
16x + 8 = 15x + 10
हल करने पर: 16x - 15x = 10 - 8 → x = 2
अब, वर्तमान आयु: समीर = 4x + 1 = 4(2) + 1 = 9 वर्ष, अशोक = 3x + 1 = 3(2) + 1 = 7 वर्ष।
उनकी वर्तमान आयु का योग = 9 + 7 = 16 वर्ष।