Which colour has the maximum deviation in the dispersion of white light…
2023
Which colour has the maximum deviation in the dispersion of white light passing through the prism?
Answer: C. Violet — Concept — Dispersion happens because the refractive index of a transparent medium is not a single fixed number: it depends on the wavelength of the light…
- A.
Green
- B.
Red
- C.
Violet
- D.
More than one of the above
- E.
None of the above
Attempted by 64 students.
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Correct answer: C
Concept — Dispersion happens because the refractive index of a transparent medium is not a single fixed number: it depends on the wavelength of the light passing through it. Cauchy's relation n = a + b/λ2 shows that n grows larger as the wavelength λ grows shorter. In a prism of refracting angle A the deviation of a ray rises steadily with the refractive index the glass presents to it — exactly, at minimum deviation, through n = sin((A + δm)/2) ÷ sin(A/2), and for a thin prism through the approximation δ ≈ (n − 1)A. On either relation, within one prism the colour that meets the largest refractive index is the colour turned through the largest angle.
Application — White light is a mixture of all visible wavelengths, so every colour in it meets a different refractive index inside the same prism:
The visible band runs from about 700 nm at its long-wavelength end (red) down to about 400 nm at its short-wavelength end (violet).
Because n = a + b/λ2, the smallest refractive index goes with the longest wavelength and the largest refractive index with the shortest wavelength. For a typical crown glass, n ≈ 1.514 at 700 nm, n ≈ 1.519 at 550 nm and n ≈ 1.532 at 400 nm.
Every colour crosses the same prism, so the refracting angle A is common to all of them. Both the exact minimum-deviation relation and the thin-prism approximation δ ≈ (n − 1)A increase with n, so the deviations fall in exactly the same order as the refractive indices.
Take a prism of refracting angle A = 10° and evaluate each ray at minimum deviation, where δm = 2 sin−1(n sin(A/2)) − A. This gives δm ≈ 5.17° for n = 1.514, δm ≈ 5.22° for n = 1.519 and δm ≈ 5.35° for n = 1.532, so the largest deviation belongs to violet, the shortest visible wavelength. The thin-prism approximation δ ≈ (n − 1)A gives 5.14°, 5.19° and 5.32° for the same three indices — different numbers, but the same ordering.
Colour | Wavelength | Refractive index n | Minimum deviation δm at A = 10° |
|---|---|---|---|
Red | ≈ 700 nm | 1.514 | 5.17° |
Green | ≈ 550 nm | 1.519 | 5.22° |
Violet | ≈ 400 nm | 1.532 | 5.35° |
Cross-check — The band thrown on a screen in Newton's prism experiment shows the same ordering. Counting away from the direction of the incoming beam the colours appear as red, orange, yellow, green, blue, indigo, violet: red lies closest to the undeviated direction and violet lies farthest from it. The angle between those two ends, δviolet − δred, is what is called the angular dispersion of the prism.
"More than one of the above" would need two of the named colours to share one single largest deviation, but n takes a different value at each of the three wavelengths, so their deviations are all distinct.
"None of the above" would put the most deviated colour outside the named list, but the short-wavelength end of the visible spectrum — the end where n is greatest — is itself one of the named colours.
Hence the colour that undergoes the maximum deviation when white light is dispersed by a prism is violet.