The multiplication of two consecutive odd numbers is 6723, then the square…

Let the two consecutive odd numbers be x and x+2. Their product is given as 6723.

So, x(x+2) = 6723

This simplifies to: x² + 2x - 6723 = 0

Solve the quadratic equation using the quadratic formula: x = [-b ± √(b² - 4ac)] / 2a

Here, a = 1, b = 2, c = -6723

Discriminant D = b² - 4ac = 4 + 26892 = 26896

√D = √26896 = 164

x = [-2 ± 164] / 2

x = (162)/2 = 81 or x = (-166)/2 = -83

The smaller positive odd number is 81.

The square root of 81 is 9.

हिन्दी उत्तर:

माना दो क्रमागत विषम संख्याएँ x और x+2 हैं। उनका गुणनफल 6723 है।

इसलिए, x(x+2) = 6723

जिसका अर्थ है: x² + 2x - 6723 = 0

द्विघात समीकरण का उपयोग करके हल करें: x = [-b ± √(b² - 4ac)] / 2a

यहाँ, a = 1, b = 2, c = -6723

विविक्तकर D = b² - 4ac = 4 + 26892 = 26896

√D = √26896 = 164

x = [-2 ± 164] / 2

x = (162)/2 = 81 या x = (-166)/2 = -83

छोटी धनात्मक विषम संख्या 81 है।

81 का वर्गमूल 9 है।