Statements: All green are blue. All blue are white Conclusions: Some blue are…
2023
Statements: All green are blue. All blue are white
Conclusions: Some blue are green.Some white are green.Some green are not white.All white are blue.
Answer: A. Only (1) and (2) — Key deduction: From the statements we have green ⊂ blue ⊂ white. So every green is also a blue and a white. Conclusion 'Some blue are green' — Follows.…
- A.
Only (1) and (2)
- B.
Only (1) and (3)
- C.
Only (1) and (4)
- D.
Only (2) and (4)
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Correct answer: A
Key deduction: From the statements we have green ⊂ blue ⊂ white. So every green is also a blue and a white.
Conclusion 'Some blue are green' — Follows. Because greens are a subset of blues and the diagram/assumption treats these sets as non-empty, there exist blues that are green.
Conclusion 'Some white are green' — Follows. Since all green are white, if greens exist then some whites are green.
Conclusion 'Some green are not white' — Does not follow. It contradicts the chain of inclusions because every green is also white.
Conclusion 'All white are blue' — Does not follow. The premises give blue ⊂ white (all blue are white), which does not imply white ⊂ blue (all white are blue).
Final answer: Only the conclusions 'Some blue are green' and 'Some white are green' follow.