Directions: Study the following information carefully and answer the questions…

Concept: When everyone in a circular arrangement faces the centre, moving to a person's LEFT corresponds to the clockwise direction around the circle, and moving to their RIGHT corresponds to the anticlockwise direction. Reading each clue as a fixed clockwise/anticlockwise offset from a known seat fixes every position uniquely; the question then reduces to checking which named person occupies the middle seat among three consecutive seats.

Application: Number the seats 1–9 clockwise and fix the seats one clue at a time.

1. Fix C at seat 1 (clockwise numbering).

2. “G is second to the right of C” — right = anticlockwise, so from seat 1 move 2 seats anticlockwise: 1→9→8. G is at seat 8.

3. “B is fourth to the left of G” — left = clockwise, so from seat 8 move 4 seats clockwise: 8→9→1→2→3. B is at seat 3.

4. “F is fourth to the right of C” — from seat 1 move 4 seats anticlockwise: 1→9→8→7→6. F is at seat 6.

5. “F is second to the left of K” means K is 2 seats anticlockwise from F: 6→5→4. K is at seat 4.

6. “A is fourth to the right of K” — from seat 4 move 4 seats anticlockwise: 4→3→2→1→9. A is at seat 9.

7. Seats 1, 3, 4, 6, 8, 9 are now taken (C, B, K, F, G, A); the three empty seats 2, 5, 7 must hold D, E and H. “H is third to the right of E” fixes E at seat 5 and H at seat 2 (5→4→3→2, three anticlockwise steps), leaving D at seat 7.

8. Check: “D is not an immediate neighbor of either K or B” — seat 7's neighbours are 6 and 8 (F and G), not K (seat 4) or B (seat 3), so the placement is consistent.

Final clockwise order: C(1)–H(2)–B(3)–K(4)–E(5)–F(6)–D(7)–G(8)–A(9).

Cross-check: re-verify every original clue against this final arrangement.

• B is fourth to the left of G: from G(8), 4 steps clockwise → 8→9→1→2→3 = B. Holds.

• G is second to the right of C: from C(1), 2 steps anticlockwise → 1→9→8 = G. Holds.

• F is fourth to the right of C: from C(1), 4 steps anticlockwise → 1→9→8→7→6 = F. Holds.

• F is second to the left of K: from K(4), 2 steps clockwise → 4→5→6 = F. Holds.

• A is fourth to the right of K: from K(4), 4 steps anticlockwise → 4→3→2→1→9 = A. Holds.

• H is third to the right of E: from E(5), 3 steps anticlockwise → 5→4→3→2 = H. Holds.

• D is not an immediate neighbor of K or B: D's neighbours (seat 7) are F(6) and G(8), not K or B. Holds.

Seat map:

For each option, check whether the third-named person is the one sitting in the middle of the three consecutive seats occupied by that trio:

• EKB — seats 5, 4, 3 hold E, K, B consecutively; the middle seat belongs to K, not the third-named B.

• CHB — seats 1, 2, 3 hold C, H, B consecutively; the middle seat belongs to H, not the third-named B.

• AGC — seats 8, 9, 1 hold G, A, C consecutively; the middle seat belongs to A, not the third-named C.

• FGD — seats 6, 7, 8 hold F, D, G consecutively; the middle seat belongs to D, exactly the third-named person.

Only in F–G–D does the third-named person occupy the middle seat between the first and second, which is the required condition.