In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up…
2025
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
Answer: A. 1/3 — Total number of balls: 8 + 7 + 6 = 21 Favourable outcomes (neither red nor green): blue balls = 7 Probability: P = favourable / total = 7 / 21 = 1/3 Step 1:…
- A.
1/3
- B.
3/4
- C.
7/19
- D.
8/21
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Show answer & explanation
Correct answer: A
Total number of balls: 8 + 7 + 6 = 21
Favourable outcomes (neither red nor green): blue balls = 7
Probability: P = favourable / total = 7 / 21 = 1/3
Step 1: Compute total balls = 8 + 7 + 6 = 21.
Step 2: Count favourable outcomes (neither red nor green) = number of blue balls = 7.
Step 3: Probability = 7 / 21 = 1/3.
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