Solve (approximate each decimal to the nearest whole number): (41.992 −…

2025

Solve (approximate each decimal to the nearest whole number): (41.992 − 18.042) ÷ ? = 13.112 − 138.99

Answer: A. 48Concept: Many quantitative-aptitude “solve for ?” items deliberately use decimals that sit very close to whole numbers (here 41.99, 18.04, 13.11, and 138.99)…

  1. A.

    48

  2. B.

    67

  3. C.

    89

  4. D.

    40

Show answer & explanation

Correct answer: A

Concept: Many quantitative-aptitude “solve for ?” items deliberately use decimals that sit very close to whole numbers (here 41.99, 18.04, 13.11, and 138.99) as a shorthand for those whole numbers — the intended method is to round each one to the nearest integer first, then work with clean integers. Once rounded, the identity a2 − b2 = (a + b)(a − b) turns the squaring on the left-hand side into a quick product.

Application:

  1. Round each decimal to the nearest whole number: 41.99 → 42, 18.04 → 18, 13.11 → 13, and 138.99 → 139.

  2. Rewrite the left-hand side using the identity a2 − b2 = (a + b)(a − b): (42 + 18)(42 − 18) ÷ ? = 132 − 139.

  3. Simplify the left-hand factors: 42 + 18 = 60 and 42 − 18 = 24, so the numerator becomes 60 × 24 = 1440.

  4. Simplify the right-hand side: 132 = 169, so 169 − 139 = 30.

  5. Solve for the unknown: 1440 ÷ ? = 30, so ? = 1440 ÷ 30 = 48.

Cross-check: Substituting back into the rounded, whole-number version of the equation confirms the result independently — 1440 ÷ 48 = 30, and the right-hand side 132 − 139 also equals 30, so both sides match exactly under the intended rounding convention.

Result: ? = 48.

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