One student secured 14 marks more than the other and his marks was 60% of the…

2023

One student secured 14 marks more than the other and his marks was 60% of the sum of their marks . Find the marks obtained by them ?

  1. A.

    38 and 24

  2. B.

    54 and 40

  3. C.

    42 and 28

  4. D.

    40 and 26

Attempted by 10 students.

Show answer & explanation

Correct answer: C

Answer: 42 and 28

  1. Let the higher mark be x and the lower mark be y.

  2. Given: x - y = 14 and x = 0.6(x + y).

  3. Substitute x = y + 14 into the second equation: y + 14 = 0.6(2y + 14) = 1.2y + 8.4.

  4. Solve: y + 14 = 1.2y + 8.4 → 14 - 8.4 = 1.2y - y → 5.6 = 0.2y → y = 28.

  5. Then x = y + 14 = 42. Therefore the marks are 42 and 28.

Quick check using percentages: The higher mark is 60% and the lower is 40% of the total, so their difference is 20% of the total. If 20% of the total = 14, total = 14 ÷ 0.20 = 70. Then 60% of 70 = 42 and 40% = 28, confirming the result.

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