The average speed of a train in the onward journey is 10% more than that in…

Step-by-Step Solution

To find the speed of the train in the onward journey, we can use the relationship between distance, speed, and time.

1. Define the variables:

   • Let the return journey speed be v km/hr.

   • Then the onward journey speed is 1.1v km/hr (since it is 10 percent more than the return speed).

   • The total distance for the round trip is 2000 km, meaning each leg (onward and return) is 1000 km.

   • Total time = 16 hours.

2. Set up the time equation:

   • Time = Distance / Speed

   • Time (onward) + Time (return) = 16 hours

   • (1000 / 1.1v) + (1000 / v) = 16

3. Solve for v:

   • (1000 / 1.1v) + (1100 / 1.1v) = 16

   • 2100 / 1.1v = 16

   • 2100 = 17.6v

   • v = 2100 / 17.6 is approximately 119.32 km/hr.

4. Calculate onward speed:

   • Onward speed = 1.1 * v = 1.1 * 119.32 is approximately 131.25 km/hr.