A bag contains 4 bananas and 3 apples. 3 fruits are taken out randomly. Find…
20232025
A bag contains 4 bananas and 3 apples. 3 fruits are taken out randomly. Find the probability of that drawn fruits is either all apples or all bananas.
Answer: C. 1/7 — Solution: Total number of fruits = 7. Number of fruits drawn = 3. Total number of ways to choose 3 fruits = C(7,3) = 35. Number of ways to get all apples =…
- A.
5/9
- B.
2/11
- C.
1/7
- D.
3/4
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Correct answer: C
Solution:
Total number of fruits = 7. Number of fruits drawn = 3.
Total number of ways to choose 3 fruits = C(7,3) = 35.
Number of ways to get all apples = C(3,3) = 1.
Number of ways to get all bananas = C(4,3) = 4.
Total favorable ways = 1 + 4 = 5.
Probability = 5/35 = 1/7.
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