The greatest number, which when subtracted from 5834, gives a number exactly…

The required number, when subtracted from 5834, should leave a number exactly divisible by 20, 28, 32, and 35.

Therefore, the remainder obtained after subtraction must be a common multiple of these numbers. To get the greatest number to be subtracted, we should leave the smallest common multiple, i.e., the LCM.

Prime factorization:

20 = 2² × 5
28 = 2² × 7
32 = 2⁵
35 = 5 × 7

LCM = 2⁵ × 5 × 7 = 1120

Now subtract this from 5834:

Required number = 5834 − 1120 = 4714

Hence, the correct answer is Option B (4714).