If the number 97215k6 is completely divisible by 11, then the smallest whole…
2023
If the number 97215k6 is completely divisible by 11, then the smallest whole number in place of 'K' would be:
- A.
2
- B.
3
- C.
7
- D.
9
Attempted by 9 students.
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Correct answer: B
We know that:
A number is divisible by 11
if difference between the sum of its digits at odd places and the sum of its digits at even places is either 0 or a number divisible by 11.
Given number = 97215k6
So, (6+5+2+9) - (k + 1 + 7) = (14 - k), which must be divisible by 11 ... K = 3