A father is twice as old as his son. 20 years ago, the age of the father was…

Step-by-Step Solution

To solve this, we can set up an equation based on the relationships described for the father's and son's ages.

1. Define Variables:

   • Let the son's present age be s.

   • Since the father is twice as old as his son, the father's present age is 2s.

2. Set up the Equation based on the past:

   • 20 years ago, the son's age was (s - 20).

   • 20 years ago, the father's age was (2s - 20).

   • The problem states that 20 years ago, the father was 12 times as old as the son: 2s - 20 = 12 * (s - 20)

3. Solve for s:

   • 2s - 20 = 12s - 240

   • 240 - 20 = 12s - 2s

   • 220 = 10s

   • s = 22 (This is the son's present age).

4. Find the Father's present age:

   • Father's age = 2s = 2 * 22 = 44.