Anil, Bhavani, Charu, Daksh, Eshaan, Farah and Gita are seven students…

Concept: In a data-arrangement puzzle with fixed slots (student, subject, college), first lock in every clue that names a value directly, then use exclusion clues to rule out remaining slots, and finally use the “one value per slot” rule to fill in whatever is left uniquely determined.

1. Daksh studies Physics in College P — this fixes his subject and college directly from the clue.

2. Farah studies History in college Q “with only Bhavani” — this fixes college Q's total membership to exactly two students, Farah and Bhavani; so Bhavani's college is Q.

3. Anil does not study in college P, Eshaan (Geology) does not study in college P, and Gita (Economics) does not study in college P — all three are excluded from P, and college Q is already full with Farah and Bhavani, so Anil, Eshaan, and Gita must all be in college R.

4. Anil studies Biology in Eshaan's college — both are already placed in college R, so this confirms Anil's subject as Biology alongside Eshaan in R.

5. Only Charu is left unplaced. College P currently holds Daksh alone, but every college needs a minimum of two students, so Charu must join Daksh in college P.

6. The subjects remaining after Physics, History, Biology, Geology and Economics are Philosophy and Chemistry, to be split between Charu and Bhavani. Since none in college P studies Chemistry (college P has neither Biology nor Chemistry), Charu — being in college P — cannot take Chemistry, so Charu studies Philosophy and Bhavani takes the remaining Chemistry.

Cross-check: the Philosophy student (Charu) is in college P, consistent with the rule that Philosophy is not studied in college R; college sizes are P = {Charu, Daksh} = 2, Q = {Bhavani, Farah} = 2, R = {Anil, Eshaan, Gita} = 3, totaling all seven students and satisfying the minimum-two-per-college rule.

Result: Daksh–Physics–College P is the only option among those given that matches the fully resolved grid, so “Daksh college P” is correct.