The octal representation of an integer is (342)8. If this were to be treated…

To find the decimal equivalent of the octal number (342)8 treated as an 8-bit signed integer in an 8085-based microprocessor, we follow these steps:

1. Convert Octal to Binary (8-bit)

Each octal digit maps directly to a 3-bit binary group:

• 3 → 011

• 4 → 100

• 2 → 010

Combining them gives the 9-bit string: 011 100 010.

Since the 8085 architecture processes 8-bit integers, we keep only the 8 least significant bits (LSBs):

Binary representation = 11100010

2. Identify the Sign of the Number

• The Most Significant Bit (MSB) is 1, which indicates that this is a negative number stored in 2's complement form.

3. Calculate the Decimal Value

To find the magnitude of a negative 2's complement number, we find its 2's complement again:

1. Invert the bits (1's complement): 00011101

2. Add 1: 00011101 + 1 = 00011110

Converting 00011110 to decimal:

(1 × 24) + (1 × 23) + (1 × 22) + (1 × 21) = 16 + 8 + 4 + 2 = 30

Since the original MSB was 1, the value is -30.