A person brought two clocks. The cost price of one of them exceeds the cost of…
2026
A person brought two clocks. The cost price of one of them exceeds the cost of the other by 1/4th. He sold the dearer one at a gain of 10% and the other at a gain of 7.5% and thus got Rs. 98 in all as S.P. Find the cost Price of the cheaper one.
Answer: A. Rs. 40 — Let the cost price of the cheaper clock be x. The dearer clock costs x + x/4 = 5x/4. Selling price of the dearer at 10% gain: 11x/8 (since (5x/4)×1.10 =…
- A.
Rs. 40
- B.
Rs. 44
- C.
Rs. 10
- D.
Rs. 490
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Correct answer: A
Let the cost price of the cheaper clock be x.
The dearer clock costs x + x/4 = 5x/4.
Selling price of the dearer at 10% gain: 11x/8 (since (5x/4)×1.10 = (5x/4)×11/10 = 11x/8).
Selling price of the cheaper at 7.5% gain: 43x/40 (since 7.5% = 3/40, so x×(1+3/40)=x×43/40).
Total selling price = 11x/8 + 43x/40 = 49x/20.
Given total selling price is Rs. 98, so 49x/20 = 98. Solving gives x = 98×20/49 = 40.
Therefore the cost price of the cheaper clock is Rs. 40.