A person brought two clocks. the cost price of one of them exceeds the cost of…
2025
A person brought two clocks. the cost price of one of them exceeds the cost of the other by 1/4th. he sold the dearer one at a gain of 10% an the other at a gain of 7.5% and thus got rs 98 in all as S.P. Find the cost Price of the cheaper one.
Answer: A. 40 — Solution: Let the cost price of the cheaper clock be x. Cost price of the other (dearer) clock = x + x/4 = 5x/4. Selling price of the dearer clock at 10% gain…
- A.
40
- B.
45
- C.
50
- D.
60
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Correct answer: A
Solution: Let the cost price of the cheaper clock be x.
Cost price of the other (dearer) clock = x + x/4 = 5x/4.
Selling price of the dearer clock at 10% gain = 1.10 × 5x/4 = 1.375x.
Selling price of the cheaper clock at 7.5% gain = 1.075x.
Total selling price = 1.375x + 1.075x = 2.45x, and this equals 98 given in the problem.
So 2.45x = 98 ⇒ x = 98 ÷ 2.45 = 40.
Answer: Rs 40