Four men finish painting a wall in 10 days. Six boys do the same job in 8…

2023

Four men finish painting a wall in 10 days. Six boys do the same job in 8 days. In how many days will 8 men and 8 boys working together paint two such walls of the same size?

  1. A.

    47/9 days

  2. B.

    28/11 days

  3. C.

    42/9 days

  4. D.

    60/11 days

Attempted by 3 students.

Show answer & explanation

Correct answer: D

General principle: each worker's individual daily work rate is 1 / (number of such workers x days that group alone takes); daily rates of different worker types add together to give the combined daily rate; the time to finish a given amount of work equals that amount divided by the combined daily rate.

  1. Rate of 1 man = 1/(4x10) = 1/40 of a wall per day.

  2. Rate of 1 boy = 1/(6x8) = 1/48 of a wall per day.

  3. Rate of 8 men = 8x(1/40) = 1/5 of a wall per day.

  4. Rate of 8 boys = 8x(1/48) = 1/6 of a wall per day.

  5. Combined rate = 1/5 + 1/6 = 6/30 + 5/30 = 11/30 of a wall per day.

  6. Time for 1 wall = 30/11 days.

  7. Time for 2 walls = 2 x (30/11) = 60/11 days.

Cross-check: (60/11) days x (11/30) wall per day = 2 walls, matching the requirement of two walls -- confirming the result.

So 8 men and 8 boys working together will paint two such walls in 60/11 days.

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