Four men finish painting a wall in 10 days. Six boys do the same job in 8…
2023
Four men finish painting a wall in 10 days. Six boys do the same job in 8 days. In how many days will 8 men and 8 boys working together paint two such walls of the same size?
- A.
47/9 days
- B.
28/11 days
- C.
42/9 days
- D.
60/11 days
Attempted by 3 students.
Show answer & explanation
Correct answer: D

General principle: each worker's individual daily work rate is 1 / (number of such workers x days that group alone takes); daily rates of different worker types add together to give the combined daily rate; the time to finish a given amount of work equals that amount divided by the combined daily rate.
Rate of 1 man = 1/(4x10) = 1/40 of a wall per day.
Rate of 1 boy = 1/(6x8) = 1/48 of a wall per day.
Rate of 8 men = 8x(1/40) = 1/5 of a wall per day.
Rate of 8 boys = 8x(1/48) = 1/6 of a wall per day.
Combined rate = 1/5 + 1/6 = 6/30 + 5/30 = 11/30 of a wall per day.
Time for 1 wall = 30/11 days.
Time for 2 walls = 2 x (30/11) = 60/11 days.
Cross-check: (60/11) days x (11/30) wall per day = 2 walls, matching the requirement of two walls -- confirming the result.
So 8 men and 8 boys working together will paint two such walls in 60/11 days.