Practice Questions Functional Dependency

Duration: 3 min

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Inside: a video lesson and guided study material.

Module outline

  1. Quantitative Ability: Speed Mathematics and Basic Mathematics, Percentage, Ratio and Proportion (Ratios), Average, Profit and Loss, Simple Interest and Compound Interest, Time and Work, Pipe and Cistern, Speed Time and Distance, Number System, HCF LCM, Data Interpretation, Age Problems, Mixture and Alligation, Partnership, Algebra, Sequence and Series (Series), Mensuration and Geometry, Arithmetic
  2. Reasoning Ability: Puzzle Solving (Puzzles), Seating Arrangements, Coding Decoding, Blood Relations, Directions (Direction Test), Syllogisms, Data Sufficiency, Ranking, Order and Sequence, Series (Number and Letter Series) (Numerical Relations and Reasoning), Logical Sequence Of Words, Calendar, Clock, Cubes & Dices, Analytical Reasoning (Counting Figures Reasoning), Data Arrangement, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning)
  3. Verbal Ability: Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Cloze Test (Cloze Passage), Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Vocabulary, Sentence Completion (Fill in the blanks), Active Passive Voice (Voice), Direct and Indirect Speech, Subject Verb Agreement (Verb Noun Agreement), Tenses, Preposition, Articles, Sentence Correction (Error Correction)
  4. Programming Basics (MCQs + Interview): C Programming by Yash Sir, Programming in C++, Java, Python for Placements by Yash Sir
  5. OOPs (MCQs + Interview): Object Oriented Programming (OOPS)
  6. DBMS (MCQs + Interview): Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Transaction Management, Decomposition Properties & 4NF, Concurrency Control, Database Recovery, File Organization & Indexing, Relational Algebra, Database Security & Authorization
  7. SQL (MCQs + Interview): SQL
  8. Operating Systems (MCQs + Interview): Introduction to OS, Process Management, CPU Scheduling, Deadlock, Threads & Process Creation, Memory Management, Virtual Memory, Process Synchronization, Disc Scheduling, File Management, Security
  9. Computer Networks (MCQs + Interview): Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics, Network Security, Mobile Technology, Cloud Computing and IoT, Cyber and Info Security
  10. Coding: Coding Questions by Yash Sir
  11. HR Interview: MR & HR Interview Preparation
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

The video lecture addresses a problem in database normalization involving the equivalence of two sets of functional dependencies, F and G, for a relation schema R(ABCDE). The instructor displays a table comparing the two sets. Set F includes the dependencies B -> CD, AD -> E, and B -> A. Set G includes B -> CDE, A -> BC, and AD -> E. The goal is to determine if F and G are equivalent. The instructor begins by calculating the closure of attributes under set F. He writes B+ = BCDE and (AD)+ = ABCDE on the board. He then checks if F covers G. He observes that B -> CDE in G is covered by B+ under F, and AD -> E is present in both. However, he notes that B -> A in F needs to be checked against G. He then switches to checking if G covers F. He calculates closures under G, writing B+ = BCDE, A+ = A, and (AD)+ = ADE. He identifies that A -> BC in G is not covered by F because A+ under F is just A. Similarly, B -> A in F is not covered by G because B+ under G is BCDE, which does not include A. He concludes that since neither set covers the other, F is not equivalent to G.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The instructor introduces the problem statement 'Consider the following set of fd R(ABCDE)' and displays a table with columns F and G. He starts analyzing set F by calculating the closure of B, writing 'B+ = BCDE' on the board. He then calculates the closure of AD, writing '(AD)+ = ABCDE'. He begins checking if F covers G, noting that B -> CDE in G is implied by B+ under F. He also notes that AD -> E is common to both. He circles B -> A in F, indicating it needs verification against G. He writes 'F != G' initially but continues the analysis to verify the reverse direction.

  2. 2:00 – 3:07 02:00-03:07

    The instructor continues the analysis by checking if G covers F. He calculates closures under G, writing 'B+ = BCDE', 'A+ = A', and '(AD)+ = ADE' on the right side of the board. He circles A -> BC in G and notes that it is not covered by F since A+ under F is just A. He also circles B -> A in F and notes it is not covered by G since B+ under G is BCDE. He writes 'G != F' and finally concludes 'F != G' at the bottom, confirming the sets are not equivalent.

The lecture provides a step-by-step demonstration of how to test for equivalence between two sets of functional dependencies. By systematically computing attribute closures for both sets, the instructor identifies specific dependencies that are not implied by the other set. This method clearly shows that F and G are distinct sets, as neither is a subset of the other's closure, leading to the conclusion that they are not equivalent.

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