CIDR Practice Question_
Duration: 4 min
This video lesson is available to enrolled students.
Inside: a video lesson and guided study material.
Module outline
- Quantitative Ability: Speed Mathematics and Basic Mathematics, Percentage, Ratio and Proportion (Ratios), Average, Profit and Loss, Simple Interest and Compound Interest, Time and Work, Pipe and Cistern, Speed Time and Distance, Number System, HCF LCM, Data Interpretation, Age Problems, Mixture and Alligation, Partnership, Algebra, Sequence and Series (Series), Mensuration and Geometry, Arithmetic
- Reasoning Ability: Puzzle Solving (Puzzles), Seating Arrangements, Coding Decoding, Blood Relations, Directions (Direction Test), Syllogisms, Data Sufficiency, Ranking, Order and Sequence, Series (Number and Letter Series) (Numerical Relations and Reasoning), Logical Sequence Of Words, Calendar, Clock, Cubes & Dices, Analytical Reasoning (Counting Figures Reasoning), Data Arrangement, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning)
- Verbal Ability: Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Cloze Test (Cloze Passage), Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Vocabulary, Sentence Completion (Fill in the blanks), Active Passive Voice (Voice), Direct and Indirect Speech, Subject Verb Agreement (Verb Noun Agreement), Tenses, Preposition, Articles, Sentence Correction (Error Correction)
- Programming Basics (MCQs + Interview): C Programming by Yash Sir, Programming in C++, Java, Python for Placements by Yash Sir
- OOPs (MCQs + Interview): Object Oriented Programming (OOPS)
- DBMS (MCQs + Interview): Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Transaction Management, Decomposition Properties & 4NF, Concurrency Control, Database Recovery, File Organization & Indexing, Relational Algebra, Database Security & Authorization
- SQL (MCQs + Interview): SQL
- Operating Systems (MCQs + Interview): Introduction to OS, Process Management, CPU Scheduling, Deadlock, Threads & Process Creation, Memory Management, Virtual Memory, Process Synchronization, Disc Scheduling, File Management, Security
- Computer Networks (MCQs + Interview): Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics, Network Security, Mobile Technology, Cloud Computing and IoT, Cyber and Info Security
- Coding: Coding Questions by Yash Sir
- HR Interview: MR & HR Interview Preparation
AI summary & chapters
AI Summary
An AI-generated summary of this video lecture.
This educational video demonstrates IP subnetting techniques using a Class C network address. The instructor begins by solving a fixed-length subnetting problem where a /24 network is divided into four equal subnets. He explains the binary borrowing process and calculates the resulting subnet IDs and ranges. The lecture concludes by introducing a more complex Variable Length Subnet Masking (VLSM) scenario requiring unequal subnet sizes.
Chapters
0:00 – 2:00 00:00-02:00
The instructor presents the problem: "Consider we have a big single network having IP Address 200.1.2.0/24 We want to do subnetting and divide this network into 4 subnets." He draws a large circle to visualize the address space. He identifies the network portion as the first three octets (200.1.2) and notes the last octet has "8 bit" available for hosts. To create 4 subnets, he explains that 2 bits must be borrowed from the host portion because 2^2 equals 4. He writes the binary combinations "00, 01, 10, 11" to represent the new subnet bits. He then begins listing the resulting subnet IDs, starting with "200.1.2.0 /26", indicating the new mask length.
2:00 – 3:34 02:00-03:34
The instructor continues the calculation, determining the block size. Since 2 bits were borrowed, 6 bits remain for hosts (8-2=6), resulting in a block size of 2^6 = 64. He lists the four subnets: 200.1.2.0/26, 200.1.2.64/26, 200.1.2.128/26, and 200.1.2.192/26. A detailed slide appears showing the "1st Subnet" through "4th Subnet" with specific details like "Direct Broadcast Address" and "Range of IP Addresses". For example, the 1st subnet range is "200.1.2.0, 200.1.2.63". The slide also calculates "Total number of hosts that can be configured = 64 - 2 = 62". Finally, a new question appears on screen: "We want to do subnetting network into 3 subnets, such that first contains 126 hosts, and other two contains 62 hosts each?" signaling a shift to VLSM.
The lesson effectively bridges basic subnetting concepts with more advanced VLSM applications. By first establishing a clear, equal division of a network, the instructor builds a strong foundation for understanding how bit borrowing affects address ranges and block sizes. The transition to the final problem highlights the practical necessity of VLSM when network requirements are not uniform, preparing students for complex network design scenarios where efficiency is key.