Important Practice Questions & Short Tricks

Duration: 6 min

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Inside: a video lesson and guided study material.

Module outline

  1. English Comprehension: Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Reading Comprehension, Vocabulary, Idioms and Phrases, Narrative Sequencing, Critical Reasoning
  2. Reasoning and Aptitude: Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Analogy, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Blood Relations, Directions (Direction Test), Ranking, Order and Sequence, Logical Sequence Of Words, Seating Arrangements, Puzzle Solving (Puzzles), Syllogisms, Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Data Sufficiency, Selection Decision Table (Decision Making), Calendar, Clock, Cubes & Dices, Data Arrangement, Venn Diagram, Analytical Reasoning (Counting Figures Reasoning), Number System, HCF LCM, Percentage, Ratio and Proportion (Ratios), Average, Profit and Loss, Simple Interest and Compound Interest, Speed Time and Distance, Mensuration and Geometry, Arithmetic, Mixture and Alligation, Age Problems, Data Interpretation, Alphabet and Word Tests, Numerical Reasoning, Number System, Averages, Mixtures and Alligation, Percentages, Series Completion, Analogy and Classification, Patterns in Two-Dimensional Figures, Coding and Decoding, Mathematical Operations, Direction Sense, Logical Deduction and Induction, Simplification and Approximation, Assembling and Grouping of Shapes, Transformation of Shapes, Three-Dimensional Patterns and Visualization, Cubes and Dice, Algebra, Traverse Surveying, Clocks and Calendars, Order, Ranking and Sequence, Constraint Puzzles, Syllogisms and Venn Diagrams, Ratio and Proportion, Mensuration, Permutations and Combinations, Project Monitoring, Resources and Safety, Profit, Loss and Discount, Sequences and Series, Powers, Surds and Logarithms, Subject-Verb Agreement, Sentence Completion, Geometry, Probability, Trigonometry, Measurement and Quantity Take-Off, Statistics, Data Sufficiency, Blood Relations, Speed, Time and Distance, Time and Work, Data Interpretation, Sequence and Series (Series), Algebra, Permutation and Combination, Combinatorics
  3. General Awareness: Physics, Chemistry, Biology, Geography, History, Polity, Indian Economy
  4. Computer Fundamentals: Basics of COA, Number System, Number Representation, Semiconductor Memories and Programmable Logic, Timing, Hazards and Testing, Processor Organization and Instructions, Number Systems and Codes, Combinational Logic Design, Combinational Logic Circuits, Number Systems and Codes
  5. Operating System: Introduction to OS, Unix OS, Linux OS
  6. C Programming: C Fundamentals, Control Flow, Functions, Arrays & Pointers, Storage Classes, Structures & Enums, DMA, Macros, Scoping & File Handling
  7. OOPS with C++ & Java: OOPS with C++, Java
  8. Database Management System: Basics of DBMS, SQL
  9. MS Office: MS Office Applications
  10. Internet & Web Technologies: Website, Browser & Services, Internet Fundamentals, Web Design & Development, Protocols & Services
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

This educational video presents a series of logical reasoning problems related to calendar calculations, typical of competitive exams. The lecture begins with a question about determining the day of the week for June 11th, 2013, given that August 15th, 2012, was a Thursday. The instructor uses a step-by-step method, calculating the number of days between the two dates and then finding the remainder when divided by 7 to determine the day of the week. The process involves identifying the number of days in each month and accounting for leap years. The video then transitions to a second problem, asking for the day of the week for January 7th, 2013, given that July 9th, 2012, was a Sunday. The final segment presents a multiple-choice question about which year among the options (2004, 2005, 2008) has 365 days, which is a test of understanding leap years. The video concludes with a 'Thanks for Watching' screen.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The video opens with a title card for a calendar problem. The first question is displayed: 'If Aug 15th, 2012 falls on Thursday then June 11th, 2013 falls on which day?'. The instructor, Yash Jain Sir, begins the solution by writing '15th Aug 2012 -> Thursday' on the blackboard. He then calculates the number of days from August 15, 2012, to August 15, 2013, which is 366 days because 2012 is a leap year. He notes that 366 mod 7 equals 2, meaning the day of the week advances by 2 days. He then calculates the number of days from June 11, 2013, to August 15, 2013, which is 65 days. He writes '65 days' and calculates 65 mod 7, which is 2. He then subtracts this from the total advance, resulting in a net advance of 0 days, concluding that June 11, 2013, is a Thursday.

  2. 2:00 – 5:00 02:00-05:00

    The instructor continues the solution for the first problem. He writes '15th Aug 2013 -> Friday' on the board, indicating the day of the week for August 15, 2013. He then calculates the number of days from June 11, 2013, to August 15, 2013, which is 65 days. He writes '65 days' and calculates 65 mod 7, which is 2. He then subtracts this from the total advance, resulting in a net advance of 0 days, concluding that June 11, 2013, is a Thursday. He then moves to the second problem: 'If July 9th, 2012 falls on Sunday then Jan 7th, 2013 falls on which day?'. He writes '9th July 2012 -> Sunday' on the board. He calculates the number of days from July 9, 2012, to July 9, 2013, which is 366 days. He notes that 366 mod 7 equals 2, meaning the day of the week advances by 2 days. He then calculates the number of days from January 7, 2013, to July 9, 2013, which is 183 days. He writes '183 days' and calculates 183 mod 7, which is 5. He then subtracts this from the total advance, resulting in a net advance of 0 days, concluding that January 7, 2013, is a Sunday.

  3. 5:00 – 5:58 05:00-05:58

    The video transitions to a new question: 'Which of the following year has 365 days?'. The options are a) 2004, b) 2005, c) 2008, d) All of the above. The instructor explains that a year with 365 days is a common year, not a leap year. He explains the rule for leap years: a year is a leap year if it is divisible by 4, but not by 100, unless it is also divisible by 400. He checks the options: 2004 is divisible by 4 and not by 100, so it is a leap year (366 days). 2005 is not divisible by 4, so it is a common year (365 days). 2008 is divisible by 4 and not by 100, so it is a leap year (366 days). Therefore, only 2005 has 365 days. The video ends with a 'Thanks for Watching' screen.

The video provides a comprehensive tutorial on solving calendar-based logical reasoning problems. It demonstrates a systematic approach: first, calculate the total number of days between two dates, then find the remainder when divided by 7 to determine the day of the week shift. The key concept is that a common year advances the day of the week by 1, while a leap year advances it by 2. The video also reinforces the rule for identifying leap years, which is essential for accurate calculations. The progression from one problem to the next builds a clear understanding of the underlying principles, making it a valuable resource for students preparing for competitive exams.

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