Practice Question (Gate 1993)
Duration: 3 min
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Module outline
- About the course: About the Course
- General Knowledge: Polity, Physics, Biology, State Wise GK, Chemistry, History, Geography, GK- Current Affairs, Indian Economy, Static General Knowledge, Environment, Evolution of Indian Banking (Banking & Financial Awareness)
- Mental Aptitude and Reasoning: Ratio and Proportion (Ratios), Divisibility Rules, Data Interpretation, Permutation and Combination, Number System, Sequence and Series (Series), Speed Time and Distance, Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Data Sufficiency, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Vocabulary, Profit and Loss, Arithmetic, Mental Ability, Percentage, Algebra, Mensuration and Geometry, Age Problems, Clock, Calendar, Verbal Analogy (Word Based Analogy), Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Analogy, Analytical Reasoning (Counting Figures Reasoning), Puzzle Solving (Puzzles), Selection Decision Table (Decision Making), Cubes & Dices, Blood Relations, Venn Diagram, Logical Sequence Of Words, Inequality, Directions (Direction Test), Data Arrangement, Facts, Inference and Judgements, Syllogisms, Seating Arrangements, Ranking, Order and Sequence
- CS | Computer Fundamentals: Basics of COA, Number System, Number Representation, C Fundamentals, Algorithm Analysis, Input Output Organisation
- CS | Database Management System: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, SQL
- CS | Workplace productivity Tools: MS Office Applications, Keyboard Shortcuts
- CS | Computer Networks: Introduction to CN, Data Communication, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Transport Layer Services, Application Layer, Hardware Basics, Network Security
- CS | The Internet: Website, Browser & Services, Internet Fundamentals, Web Design & Development, Web Publishing & Hosting, Server Side & Security, Emerging Technologies
- CS | Emerging Technologies: Artificial Intelligence, Emerging Tech Trends, Introduction to OS, Windows OS, Linux OS, Unix OS, JavaScript-Basics
- CS | Boolean algebra: Digital Systems & Boolean Basics, Boolean Expression, Boolean Minimization, Logic Gates & Hardware
- CS | Data Structures: Introduction to DS, Array, Stack, Queue
- CS | Cryptography: Society, Law & Ethics, Cyber Threats and Malware Attacks, Role of Internet and Web Services, Security in Mobile and Wireless Computing, Electronic Data Interchange and E-Commerce, Physical Security and Cryptography Basics, Intrusion Detection Systems (IDS), Cyber Safety and Security
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AI summary & chapters
AI Summary
An AI-generated summary of this video lecture.
This educational video provides a detailed walkthrough of a GATE 1993 computer organization problem involving moving arm disk storage. The instructor systematically breaks down the given specifications to calculate two key performance metrics: average latency (P) and data transfer rate (Q). The lecture focuses on converting units and applying standard formulas for disk access time and throughput.
Chapters
0:00 – 2:00 00:00-02:00
The session begins with the instructor reading the problem statement displayed on the screen. He lists the specifications: 'Number of tracks/recording surface = 200', 'Disk rotation speed = 2400 rpm', and 'Track storage capacity = 62,500 bits'. He underlines the target variables, 'average latency' and 'data transfer rate'. He starts the calculation by converting the rotation speed from rpm to rotations per second, writing '2400 / 60' on the board. This yields 40 rotations per second. Consequently, he calculates the time for one full rotation as 1/40 seconds. To make this more readable, he converts the time into milliseconds by multiplying by 1000, resulting in '25 ms' for one full rotation.
2:00 – 2:40 02:00-02:40
The instructor proceeds to find the average latency, explaining that it is half the time of one full rotation. He writes '12.5 ms' on the board, identifying this as the value for P. Next, he tackles the data transfer rate (Q). He establishes a relationship where 25 ms corresponds to the transfer of 62,500 bits. To find the rate per second, he sets up a proportion: 1 second corresponds to (62,500 / 25) * 1000 bits. He performs the division 62,500 / 25 to get 2,500, and then multiplies by 1000 to get 2,500,000. He writes the final answer as '= 2.5 x 10^6 b/s', completing the calculation for Q.
The video effectively demonstrates how to derive disk performance parameters from basic physical specifications. By first determining the rotational period, the instructor establishes the foundation for calculating both latency and transfer rates. The step-by-step board work clarifies unit conversions between seconds and milliseconds, ensuring students understand the magnitude of the values involved. This methodical approach is crucial for solving similar problems in computer architecture exams.