Binary 101110.11 is equal to –

Conversion to Decimal (Base-10)

To convert to decimal, multiply each bit by 2n where n is the position relative to the binary point:

(1 x 25) + (0 x 24) + (1 x 23) + (1 x 22) + (1 x 21) + (0 x 20) . (1 x 2-1) + (1 x 2-2)

= 32 + 0 + 8 + 4 + 2 + 0 . 0.5 + 0.25

= 46.7510

Statement II is correct.

2. Conversion to Octal (Base-8)

Group bits into sets of three starting from the binary point:

• Integer part: 101 | 110 = 5 | 6

• Fractional part: 110 = 6 (add a trailing zero to complete the triplet)

• Result: 56.68

  Statement I is correct.

3. Conversion to Hexadecimal (Base-16)

Group bits into sets of four starting from the binary point:

• Integer part: 0010 | 1110 = 2 | 14 (E)

• Fractional part: 1100 = 12 (C)

• Result: 2E.C16

  Statement III is correct.