What is the output of the following code written in C?
void main()
{
printf("%d%d%d", 62, 062, 0x62);
}

Question

What is the output of the following code written in C? void main() { printf("%d%d%d", 62, 062, 0x62); }

Accepted Answer

Correct answer: C — The code uses printf with three integer arguments formatted as %d. First argument: 62 is a decimal integer, so it prints as 62. Second argument: 062 starts with 0, indicating octal. 6*8 + 2 = 50. Third argument: 0x62 indicates hexadecimal. 6*16 + 2 = 98. The format string %d%d%d prints them consecutively, resulting in 625098.

Answer

A. 506298

Answer

B. 629850

Answer

C. 625098

Answer

D. 986250

What is the output of the following code written in C? void main() {…