Stack Practice questions
Duration: 5 min
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Inside: a video lesson and guided study material.
Module outline
- About Course: About the Course
- CS | 01 | Digital Logic and Circuits and Discrete Mathematical Structures: Digital Systems & Boolean Basics, Number System, Number Representation, Logic Gates & Hardware, Boolean Expression, Boolean Minimization, Combinational Circuit, Sequential Circuits, Set Theory, Relations, Functions, Graph Theory, Group Theory, Propositional and Predicate Logic, Permutation and Combination
- CS | 02 | Computer Organization and Architecture: Basics of COA, Cache Memory Organization, Input Output Organisation, Pipelining, Instr Formats & Modes, Control Unit Design, Multiprocessors
- CS | 03 | Data Structures and Algorithm: Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing, Algorithm Analysis, Time Complexity Analysis, Sorting Algorithms, Greedy Algorithms, Dynamic Programming, Minimum Spanning Trees, Shortest Path Algos, Complexity Theory, Advanced Algorithms
- CS | 04 | Problem Solving through C Programming: C Fundamentals, Control Flow, Functions, Arrays & Pointers, Storage Classes, Structures & Enums, DMA, Macros, Scoping & File Handling
- CS | 05 | Object Oriented Techniques: Object Oriented Technology, Java
- CS | 06 | Operating System: Introduction to OS, Process Management, CPU Scheduling, Process Synchronization, Threads & Process Creation, Deadlock, Memory Management, Virtual Memory, Disc Scheduling, File Management, Windows OS, Unix OS
- CS | 07 | Database Management Systems: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, Relational Algebra, SQL, Relational Calculus, Transaction Management, Concurrency Control, Database Recovery, Database Security & Authorization, Query Processing & Optimization, File Organization & Indexing
- CS | 08 | Computer Networks: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics
- CS | 09 | Software Engineering: Fundamentals of Software Engineering, Software Requirements and Quality Assurance, Software Design, Estimation and Metrics, Software Testing, Software Maintenance and Configuration Management
- CS | 10 | Internet Technology, Web Design and Web Technology: Internet Fundamentals, Web Design & Development, Protocols & Services, Web Publishing & Hosting, Server Side & Security, Emerging Technologies, JavaScript-Basics, HTML Basics
- CS | 11 | System Analysis And Design: Fundamentals of Systems and Information Systems, SDLC and Development Approaches, Software Documentation and Software Requirements Specification (SRS), SDD and Quality Assurance, Security, Risk Management & Maintenance
- CS | 12 | Information Security and Cyber Laws: Cyber Threats and Malware Attacks, Role of Internet and Web Services, Security in Mobile and Wireless Computing, Electronic Data Interchange and E-Commerce, Physical Security and Cryptography Basics, Intrusion Detection Systems (IDS), Cyber Safety and Security
- CS | 13 | Computer Graphics: Basics of Computer Graphics, 2-D Geometrical Transforms and Viewing, 3-D Object Representation, Geometric Transformations and Viewing
- GS Paper | 01 | Indian and World Geography: Geography
- GS Paper | 02 | History: History
- GS Paper | 03 | Indian Economy & Social Development: Indian Economy
- GS Paper | 04 | General Science: Biology, Chemistry, Physics
- GS Paper | 05 | Elementary Maths: Number System, Divisibility Rules, HCF LCM, Percentage, Profit and Loss, Simple Interest and Compound Interest, Ratio and Proportion (Ratios), Average, Time and Work, Speed Time and Distance, Algebra, Mensuration and Geometry, Data Interpretation, Arithmetic, Statistics, Probability, Sequence and Series (Series), Mixture and Alligation, Calculus, Trigonometry, Vectors
- GS Paper | 06 | Indian Polity and Governance: Polity
- GS Paper | 07 | Current Events: GK- Current Affairs
- UPLT Live Classes Notes: UPLT Live Classes
- UPLT Full Mock Tests Tier 1:
- UPLT Full Mock Tests Tier 2:
AI summary & chapters
AI Summary
An AI-generated summary of this video lecture.
The video presents a C programming problem asking students to predict the output of a recursive function f(n) called with the argument 11. The instructor systematically traces the execution of the code, analyzing the base cases and recursive steps. He writes down the call tree on the whiteboard, breaking down f(11) into smaller sub-problems like f(5) and f(6). By evaluating each recursive call step-by-step, determining return values based on integer division and modulo operations, he calculates the final result. The process involves checking conditions like n <= 1 and n % 2 == 0 to decide the return path. The final output is determined to be 5, corresponding to option (D).
Chapters
0:00 – 2:00 00:00-02:00
The instructor introduces the problem "Predict the output of following program" and displays the C code on screen. He starts tracing the function f(11) written on the board. He evaluates the first condition if(n <= 1) as false for 11. Then he checks if(n%2 == 0), noting that 11 is odd, so this is also false. Consequently, he moves to the final return statement return f(n/2) + f(n/2+1), substituting 11 to get return f(5) + f(6). He begins expanding f(5) by writing Ret f(2) + f(3) underneath it, indicating the next level of recursion. He then analyzes f(2), checking 2 <= 1 (false) and 2%2 == 0 (true), leading to return f(1). He establishes that f(1) returns 1 because 1 <= 1 is true, writing f(2) = 1 on the side.
2:00 – 5:00 02:00-05:00
Continuing the trace, the instructor evaluates f(3). Since 3 is odd, it hits the final return statement: return f(1) + f(2). Using the previously calculated values where f(1) = 1 and f(2) = 1, he determines f(3) = 2. He writes f(3) = 2 on the board. Returning to f(5), he sums the results of its children: f(2) + f(3) becomes 1 + 2, so f(5) = 3. Next, he analyzes f(6). Since 6 is even, the condition n%2 == 0 is true, so it returns f(6/2) which is f(3). Since f(3) is already known to be 2, f(6) = 2. Finally, he combines the results for the initial call: f(11) = f(5) + f(6) becomes 3 + 2, resulting in 5. He writes f(11) = 5 clearly on the board.
5:00 – 5:08 05:00-05:08
The instructor concludes the problem by confirming the calculated result is 5. He points to option (D) 5 and places a checkmark next to it, indicating it is the correct answer. He briefly dismisses the other options, crossing out (A) Stack Overflow, (B) 3, and (C) 4 to show they are incorrect. The video ends with the final answer selected.
The lecture demonstrates a methodical approach to solving recursive function problems by manually tracing the call stack. The instructor breaks down complex calls into simpler sub-problems, utilizing a top-down expansion strategy. By calculating base cases first and working backwards up the recursion tree, he avoids stack overflow errors and correctly computes the final integer value. This step-by-step evaluation highlights the importance of understanding integer division and modulo operators in C recursion.