Practice Question - 2
Duration: 2 min
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Inside: a video lesson and guided study material.
Module outline
- About Course: About the Course
- CS | 01 | Digital Logic and Circuits and Discrete Mathematical Structures: Digital Systems & Boolean Basics, Number System, Number Representation, Logic Gates & Hardware, Boolean Expression, Boolean Minimization, Combinational Circuit, Sequential Circuits, Set Theory, Relations, Functions, Graph Theory, Group Theory, Propositional and Predicate Logic, Permutation and Combination
- CS | 02 | Computer Organization and Architecture: Basics of COA, Cache Memory Organization, Input Output Organisation, Pipelining, Instr Formats & Modes, Control Unit Design, Multiprocessors
- CS | 03 | Data Structures and Algorithm: Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing, Algorithm Analysis, Time Complexity Analysis, Sorting Algorithms, Greedy Algorithms, Dynamic Programming, Minimum Spanning Trees, Shortest Path Algos, Complexity Theory, Advanced Algorithms
- CS | 04 | Problem Solving through C Programming: C Fundamentals, Control Flow, Functions, Arrays & Pointers, Storage Classes, Structures & Enums, DMA, Macros, Scoping & File Handling
- CS | 05 | Object Oriented Techniques: Object Oriented Technology, Java
- CS | 06 | Operating System: Introduction to OS, Process Management, CPU Scheduling, Process Synchronization, Threads & Process Creation, Deadlock, Memory Management, Virtual Memory, Disc Scheduling, File Management, Windows OS, Unix OS
- CS | 07 | Database Management Systems: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, Relational Algebra, SQL, Relational Calculus, Transaction Management, Concurrency Control, Database Recovery, Database Security & Authorization, Query Processing & Optimization, File Organization & Indexing
- CS | 08 | Computer Networks: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics
- CS | 09 | Software Engineering: Fundamentals of Software Engineering, Software Requirements and Quality Assurance, Software Design, Estimation and Metrics, Software Testing, Software Maintenance and Configuration Management
- CS | 10 | Internet Technology, Web Design and Web Technology: Internet Fundamentals, Web Design & Development, Protocols & Services, Web Publishing & Hosting, Server Side & Security, Emerging Technologies, JavaScript-Basics, HTML Basics
- CS | 11 | System Analysis And Design: Fundamentals of Systems and Information Systems, SDLC and Development Approaches, Software Documentation and Software Requirements Specification (SRS), SDD and Quality Assurance, Security, Risk Management & Maintenance
- CS | 12 | Information Security and Cyber Laws: Cyber Threats and Malware Attacks, Role of Internet and Web Services, Security in Mobile and Wireless Computing, Electronic Data Interchange and E-Commerce, Physical Security and Cryptography Basics, Intrusion Detection Systems (IDS), Cyber Safety and Security
- CS | 13 | Computer Graphics: Basics of Computer Graphics, 2-D Geometrical Transforms and Viewing, 3-D Object Representation, Geometric Transformations and Viewing
- GS Paper | 01 | Indian and World Geography: Geography
- GS Paper | 02 | History: History
- GS Paper | 03 | Indian Economy & Social Development: Indian Economy
- GS Paper | 04 | General Science: Biology, Chemistry, Physics
- GS Paper | 05 | Elementary Maths: Number System, Divisibility Rules, HCF LCM, Percentage, Profit and Loss, Simple Interest and Compound Interest, Ratio and Proportion (Ratios), Average, Time and Work, Speed Time and Distance, Algebra, Mensuration and Geometry, Data Interpretation, Arithmetic, Statistics, Probability, Sequence and Series (Series), Mixture and Alligation, Calculus, Trigonometry, Vectors
- GS Paper | 06 | Indian Polity and Governance: Polity
- GS Paper | 07 | Current Events: GK- Current Affairs
- UPLT Live Classes Notes: UPLT Live Classes
- UPLT Full Mock Tests Tier 1:
- UPLT Full Mock Tests Tier 2:
AI summary & chapters
AI Summary
An AI-generated summary of this video lecture.
This educational video segment presents a solved problem from the GATE 2017 examination concerning computer architecture, specifically focusing on direct-mapped cache memory calculations. The instructor analyzes a byte-addressable machine with 2^32 bytes of main memory and a block size of 32 bytes. The core task is to determine the bit size of the tag field given a cache with 512 lines. The visual content displays structured diagrams partitioning the physical address into Tag, Cache Line (Index), and Block Offset components. The solution involves calculating the offset bits from the block size, deriving the index bits from the number of cache lines, and subtracting these from the total address width to find the tag size.
Chapters
0:00 – 1:51 00:00-01:51
The instructor introduces a GATE 2017 problem on direct-mapped cache memory, displaying the question text: 'Consider a machine with byte addressable memory of 2^32 bytes divided into blocks of size 32 bytes.' The visual diagrams illustrate the physical address structure, explicitly labeling 'Main Memory (Physical Address) 32' bits. The instructor breaks down the address fields, showing that a block size of 32 bytes requires 5 bits for the Block Offset (since 2^5 = 32). The diagram further indicates that with 512 cache lines, the Cache Line index requires 9 bits (since 2^9 = 512). The final calculation partitions the 32-bit address into Block Number (27 bits) and Block Offset (5 bits), leading to the conclusion that the Tag field size is 18 bits, derived by subtracting the index and offset bits from the total address width.
The video provides a concise walkthrough of cache address mapping, emphasizing the relationship between memory parameters and bit allocation. Key evidence includes the on-screen text specifying '2^32 bytes' memory size and '512 cache lines,' alongside diagrams showing the 32-bit address split. The instructor demonstrates that Block Offset is determined by log2(block size) and Cache Line Index by log2(number of lines). The Tag field is the remainder. This problem reinforces the standard formula: Total Address Bits = Tag + Index + Offset. The solution confirms that for a 32-bit address, with 5 offset bits and 9 index bits, the Tag must be 18 bits. This aligns with option (C) in the multiple-choice question presented.