Read the following information given below and answer the question that…

Concept: When people sit facing the centre of a circle, moving to a person's left corresponds to moving clockwise around the circle (facing inward reverses the usual left–right sense), and "neighbour" means the seat immediately next to a person on either side. A fixed circular arrangement is solved by converting each relative clue — second-to-the-left, neighbour-of, not-a-neighbour-of — into concrete seat offsets and building up one consistent seating, then checking every clue against it.

Application: Building the seating step by step from the clues:

1. V is second to the left (two seats clockwise) of S, and V's only two neighbours are T and U — so the seat immediately clockwise of S and the seat immediately clockwise of V together must be T and U.

2. S is not a neighbour of T (clue iii), so the seat right after S cannot be T — it must be U instead, which makes the seat right after V equal to T.

3. This fixes four consecutive seats clockwise as S, U, V, T, leaving three seats for P, Q and R.

4. P is a neighbour of both Q and R (clue iv), so P must occupy the middle of the three remaining seats, with Q and R on either side of it.

5. S is also not a neighbour of R (clue iii), so the seat immediately before S — the last of the three remaining seats — cannot be R; it must be Q, which places R at the other end, next to T.

6. The complete clockwise seating is therefore S, U, V, T, R, P, Q (and back to S).

Cross-check: Verifying every clue against this seating:

• V is two seats clockwise of S (S → U → V) and its neighbours are U and T — matches clue ii.

• S's neighbours are Q and U, neither of which is R or T — matches clue iii.

• P's neighbours are R and Q — matches clue iv.

Answer: In this seating, U's two neighbours are V and S, so U sits directly between V and S — the triplet V, U, S.