X = 101102103104105106107......146147148149150 (From numbers 101-150). Find…
2025
X = 101102103104105106107......146147148149150 (From numbers 101-150). Find out the remainder when this number is divided by 9.
Answer: D. 2 — The divisibility rule for 9 is sum of the digits is to be divisible by 9. So We calculate separately, sum of the digits in hundreds place, tenths place, and…
- A.
3
- B.
0
- C.
1
- D.
2
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Correct answer: D
The divisibility rule for 9 is sum of the digits is to be divisible by 9. So
We calculate separately, sum of the digits in hundreds place, tenths place, and units place.
Sum of the digits in hundreds place: 1 x 50 = 50
Sum of the digits in tenths place : 0 x 9 + 1 x 10 + 2 x 10 + 3 x 10 + 4 x 10 + 5 x 1 = 105
Sum of the digits in units place : (1 + 2 + 3 + ...+ 9) x 5 = 225
So total = 380
So remainder = 380 / 9 = 2