In a race from point X to point Y and back, Jack averages 30 miles/hr to pt Y…
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In a race from point X to point Y and back, Jack averages 30 miles/hr to pt Y and 10 miles/hr back to pr X. Sandy averages 20 miles/hr in both directions. If Jack and Sandy start race at same time, who'll finish first ?
Answer: A. Sandy — Answer: Sandy Reasoning: For a round trip where the outward speed is a and the return speed is b, the average speed over the whole trip is 2ab/(a+b). Jack:…
- A.
Sandy
- B.
Jack
- C.
They tie
- D.
Impossible to tell
Attempted by 734 students.
Show answer & explanation
Correct answer: A
Answer: Sandy
Reasoning:
For a round trip where the outward speed is a and the return speed is b, the average speed over the whole trip is 2ab/(a+b).
Jack: outward 30 mph, return 10 mph → average = 2×30×10/(30+10) = 600/40 = 15 mph
Sandy: 20 mph each way → average = 2×20×20/(20+20) = 800/40 = 20 mph
Conclusion: Since Sandy's average speed (20 mph) is greater than Jack's (15 mph), Sandy finishes the round trip first. This conclusion does not depend on the distance of the race.
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