Three dice are rolled. What is the probability of sum of the numbers on the…

Total nos of possible outcome : 6x6x6 = 216

For the sum to be 10 : x + y + z = 10

The following combinations are possible:

(6,3,1) : 3! ways = 6

(6,2,2) : 3!/2 ways = 3

(5,4,1) : 3! ways = 6

(5,3,2) : 3! ways = 6

(4,4,2) : 3!/2 ways = 3

(4,3,3) : 3!/2 ways = 3

So total ways : 27

Required probability : 27/216 = 1/8