Practice Questions

Duration: 11 min

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Inside: a video lesson and guided study material.

Module outline

  1. General Intelligence & Reasoning: Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Analogy, Analytical Reasoning (Counting Figures Reasoning), Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Syllogisms, Puzzle Solving (Puzzles), Venn Diagram, Clerical Aptitude, Verbal Classification
  2. General Awareness: Polity, Physics, Biology, Chemistry, History, Geography, Indian Economy, Environment, GK- Current Affairs, Static General Knowledge
  3. Quantitative Aptitude: Ratio and Proportion (Ratios), Data Interpretation, Mixture and Alligation, Number System, Speed Time and Distance, Percentage, Average, Arithmetic, Simple Interest and Compound Interest, Profit and Loss, Partnership, Time and Work, Algebra, Mensuration and Geometry, Trigonometry, Linear Algebra
  4. English Comprehension: Vocabulary, Noun, Subject Verb Agreement (Verb Noun Agreement), Adjectives, Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Pronoun, Preposition, Articles, Adverb, Interjection, Conjunction, Modals, Determiner, Active Passive Voice (Voice), Direct and Indirect Speech, Verbal Analogy (Word Based Analogy), Cloze Test (Cloze Passage), Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Sentence Correction (Error Correction), Sentence Completion (Fill in the blanks)
  5. MOCK TEST:
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

This educational video is a lecture on calculating profit in scenarios involving dishonest weight practices, a common topic in aptitude and placement exams. The instructor begins by presenting a problem where a shopkeeper sells onions at a 10% profit but uses a weight that is 20% less than the original. He then introduces a general formula for calculating total profit: (Profit% + Decrease% in weight) / (100 - Decrease% in weight) * 100. He applies this formula to solve the first problem, arriving at a total profit of 37.5%. The lecture continues with a second example, where a shopkeeper claims to sell per kg but uses 960 grams instead of 1 kg, and a third example with a fruit vendor using 900 grams for a kg. The instructor consistently uses the same formula to solve each problem, demonstrating its application. The video concludes with a final summary of the method and a thank you message.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The video opens with a conceptual image of a 3D figure standing on a seesaw, with 'PROFIT' in green on one side and 'LOSS' in red on the other, symbolizing the balance of financial outcomes. The scene then transitions to a lecture format, where the instructor presents the first problem: 'A shopkeeper sells onion on a profit of 10%. The weight he uses is 20% less than original weight. What will be his total profit?'. The options are listed as a) 17.5%, b) 27.5%, c) 37.5%, d) 47.5%. The instructor introduces the problem, which is noted as an 'IMPORTANT QUESTION ASKED IN IBM EXAM (2018)'. The visual includes a humorous image of a woman crying while holding a small onion in a box, with a tweet overlay about onion prices, adding a comedic element to the serious topic.

  2. 2:00 – 5:00 02:00-05:00

    The instructor begins to solve the first problem by writing the formula for total profit on a green chalkboard. The formula is clearly written as: Profit% = (Profit% + decrease% in weight) / (100 - decrease% in weight) * 100. He then substitutes the values from the problem: Profit% = 10 and Decrease% in weight = 20. The calculation is shown step-by-step: (10 + 20) / (100 - 20) * 100, which simplifies to 30 / 80 * 100. The instructor explains that this calculation results in 37.5%. He confirms that the correct answer is option (c) 37.5%. The visual shows the instructor's hand writing the formula and calculations in yellow chalk, with the problem statement and options visible at the top of the screen.

  3. 5:00 – 10:00 05:00-10:00

    The instructor moves to a second problem: 'A shopkeeper claims to sell per kg NIRMA on the cost price but he uses a weight of 960 grams instead of 1 Kg. How much percentage of profit he earns by doing this?'. He applies the same formula, writing it on the board: Profit% = (Profit% + decrease% in weight) / (100 - decrease% in weight) * 100. He identifies the profit% as 0 (since he sells at cost price) and the decrease% in weight as (1000 - 960) / 1000 * 100 = 4%. The calculation becomes (0 + 4) / (100 - 4) * 100, which is 4 / 96 * 100. He simplifies this to 25 / 6, which equals 4 + 1/6%. He then presents a third problem: 'A dishonest fruit vendor sells his goods at Cost Price, but he uses 900 gm instead of 1 kg weight, his gain percent is'. He applies the formula again, with profit% = 0 and decrease% in weight = 10%. The calculation is (0 + 10) / (100 - 10) * 100 = 10 / 90 * 100 = 100 / 9 = 11 + 1/9%. The instructor emphasizes that this is a standard method for solving such problems.

  4. 10:00 – 10:35 10:00-10:35

    The video concludes with a final summary of the method. The instructor reiterates the formula for calculating profit when a dishonest shopkeeper uses a lesser weight. The screen displays a blue, abstract background with the text 'THANKS FOR WATCHING' in large white letters. The instructor's voiceover thanks the viewers for watching and mentions that a quiz containing important previous year IT companies' questions will be discussed at the end of the video, encouraging viewers to watch until the end.

The video provides a clear and structured lesson on a specific type of profit and loss problem. It begins by introducing a real-world scenario involving a dishonest shopkeeper, which is a common theme in aptitude tests. The core of the lesson is the derivation and application of a single, powerful formula: Profit% = (Profit% + decrease% in weight) / (100 - decrease% in weight) * 100. The instructor demonstrates this formula with three distinct examples, each with different values, reinforcing the method's versatility. The progression from a simple problem to more complex ones, all solved using the same formula, effectively teaches a universal problem-solving technique. The use of a green chalkboard for calculations and clear, step-by-step writing makes the method easy to follow and replicate for students preparing for competitive exams.

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