A vessel contains 72 liters mixture of milk and water in the ratio of 5 : 3…
2025
A vessel contains 72 liters mixture of milk and water in the ratio of 5 : 3 respectively. 40 liters mixture is taken out and x liters of pure milk added in the remaining mixture. If the quantity of milk becomes 7 times of the water in the final mixture, then find the value of x?
Answer: E. 64 — Initial mixture is 72 liters with milk:water = 5:3, so milk = 45 liters and water = 27 liters. After removing 40 liters, 32 liters remain with milk = 20…
- A.
72
- B.
48
- C.
68
- D.
60
- E.
64
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Correct answer: E
Initial mixture is 72 liters with milk:water = 5:3, so milk = 45 liters and water = 27 liters.
After removing 40 liters, 32 liters remain with milk = 20 liters and water = 12 liters.
After adding x liters of pure milk, (20 + x) : 12 = 7 : 1, so 20 + x = 84 and x = 64.
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