Practice Question - Primary Indexing Cont...

Duration: 8 min

This video lesson is available to enrolled students.

Return to /learn/RSSB-SENIOR-COMPUTER-INSTRUCTOR/paper-2-database-management-system/file-organization-indexing/basics-types-of-indexing/asset-practice-question-primary-indexing-cont after enrolling

Inside: a video lesson and guided study material.

Module outline

  1. About the Course: About the Course
  2. Paper-1 & 2 | Basic Numeracy: Ratio and Proportion (Ratios), Divisibility Rules, Mixture and Alligation, Permutation and Combination, Logarithm, Number System, HCF LCM, Sequence and Series (Series), Speed Time and Distance, Percentage, Average, Mensuration and Geometry, Age Problems, Arithmetic, Statistics, Probability, Profit and Loss, Simple Interest and Compound Interest, Partnership, Speed Mathematics and Basic Mathematics, Algebra, Powers and Exponents (Surds and Indices), Time and Work, Pipe and Cistern, RSSB Specific Videos - Basic Numeracy
  3. Paper-1 & 2 | Data Interpretation: Data Interpretation
  4. Paper-1 & 2 | General Mental Ability: Mental Ability, RSSB Specific Videos - Mental Ability
  5. Paper-1 & 2 | Logical Reasoning and Analytical Ability: Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Data Sufficiency, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Syllogisms, Seating Arrangements, Blood Relations, Directions (Direction Test), Analytical Reasoning (Counting Figures Reasoning), Puzzle Solving (Puzzles), Calendar, Clock, Cubes & Dices, Venn Diagram, Analogy, Ranking, Order and Sequence, Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Data Arrangement, Logical Sequence Of Words, Crypt Arithmetic
  6. Paper-1 & 2 | Decision Making and Problem Solving: Selection Decision Table (Decision Making)
  7. Paper-1 | General Science: Physics, Biology, Chemistry, RSSB Specific Videos
  8. Paper-1 | General Awareness: State Wise GK, GK- Current Affairs
  9. Paper-2 | Fundamentals of Computer: Basics of COA, Number System, Floating Point Rep, Number Representation
  10. Paper - 2 | Digital Logic Systems: Digital Systems & Boolean Basics, Logic Gates & Hardware, Boolean Expression, Boolean Minimization, Combinational Circuit, Sequential Circuits
  11. Paper-2 | Operating Systems: Introduction to OS, Process Management, CPU Scheduling, Process Synchronization, Deadlock, Threads & Process Creation, Memory Management, Virtual Memory, Disc Scheduling, File Management, Linux OS, Distributed Systems
  12. Paper-2 | Database Management System: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, Relational Algebra, SQL, Relational Calculus, File Organization & Indexing, Transaction Management, Concurrency Control
  13. Paper-2 | Data Structures: Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing
  14. Paper-2 | C Programming: C Fundamentals, Control Flow, Functions, Arrays & Pointers, Storage Classes, Structures & Enums, DMA, Macros, Scoping & File Handling
  15. Paper 2 | Oops, C++, Java: Language Design, OOPS with C++, Java, .Net Programming, Java Fundamentals
  16. Paper 2 | Python: Introduction to Python, Tokens, Variables, Data Types, I/O, Operators & Expressions, Control Flow & Looping, Collections & Strings, Functions & Modules, File Handling & Data Analysis
  17. Paper 2 | Emerging Trends and AI: Emerging Tech Trends, Artificial Intelligence
  18. Paper-2 | Algorithms: Algorithm Analysis, Time Complexity Analysis, Sorting Algorithms, Greedy Algorithms, Advanced Algorithms
  19. Paper 2 | Data Communication and Network Security: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics, Network Security, Ethical Hacking
  20. Paper-2 I Software Engineering: Fundamentals of Software Engineering, Software Requirements and Quality Assurance, Software Design, Estimation and Metrics, Software Testing, Software Maintenance and Configuration Management
  21. Paper-2 | Computer Organization and Architecture: Cache Memory Organization, Input Output Organisation, Instr Formats & Modes, Control Unit Design, Register Transfer and Microoperations
  22. Paper-2 | Web Development: JavaScript-Basics, HTML Basics, CSS, XML
  23. Pedagogy: Child Development, Concept of Pedagogy, Psychology, Theories, Inclusive Education, Experiential Pedagogy, Curriculum Framework & Reforms, National Education Policy (NEP) 2020
  24. Live Sessions: RSSB Live Sessions
  25. RSSB Paper 1 - Full Mock Tests:
  26. RSSB Paper 2 - Full Mock Tests:
  27. SCI Previous Year Papers:
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

This lecture video works through a primary indexing practice question for an ordered file. The problem states: suppose we have an ordered file with records stored, r = 30,000, on a disk with Block Size B = 1024 B, record length R = 100 B, a 9 B key field, and a 6 B block pointer. The instructor asks how to implement primary indexing. The solution proceeds in steps: first compute the blocking factor BF = floor(1024 / 100) = [10.24] = 10 records per block (one frame shows a variant BF = floor((1024 - 8)/100) = [10.16] = 10, suggesting possible overhead subtraction). Then compute the number of data blocks: n = r / BF = 30,000 / 10 = 3,000 blocks. Then compute the number of index entries needed: one per data block = 3,000. Each index entry is key (9 B) + pointer (6 B) = 15 B. The number of index entries per block is floor(1024 / 15) = [68.2] = 68. The number of index blocks at the first level is ceil(3000 / 68) = [44.11] -> 45 blocks (rounded up in a later frame). A logarithmic calculation log2(3000) = [11...7] -> 12 is also shown, which appears to relate to pointer size or a related bound. Hand-drawn diagrams show index blocks with 9 B key and 6 B pointer fields (15 B total) linked to stacked data blocks labeled 30,000. The teaching flow moves from problem statement, to blocking factor, to block count, to index entry size and multi-level structure.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The orange problem statement at the top reads 'Q Suppose we have ordered file with records stored r = 30,000 on a disk with Block Size B = 1024 B' and ends 'Implement primary indexing?'. Red handwritten work on the left shows BF = 1024 / 100 B = [10.24] = 10, then = 30000 / 10 = 3000, and log2(3000) = [11...7] = 12. A red block diagram on the right shows stacked rectangles labeled '9 B', a pointer line marked '6 B', and a bottom block labeled '30,000'. The instructor establishes the blocking factor as 10 records per block and the total data blocks as 3,000.

  2. 2:00 – 5:00 02:00-05:00

    The whiteboard continues the primary indexing solution. The instructor writes BF = (1024 - 8) / 100 B = [10.16] = 10 in one frame, indicating a possible overhead adjustment, while other frames show BF = 1024 / 100 = [10.24] = 10. The total blocks remain 30,000 / 10 = 3,000. The index block diagram is drawn with key (9 B) and pointer (6 B) fields, totaling 15 B per entry. The log2(3000) = [11...7] = 12 calculation is shown, relating to the index structure. The instructor visualizes the relationship between file blocks and index entries on the whiteboard.

  3. 5:00 – 7:39 05:00-07:39

    A middle column computes BF = 1024/15, [68.2] = 68 index entries per block, then [3000/68] = [44.11], with the rounded value 45 added in a later frame for the number of first-level index blocks. Hand-drawn index block diagrams on the right carry labels KG, 9B, 6B and 15B, with arrows linking them to a stacked multi-level structure. The left column retains BF = 1024/100 = [10.24] = 10, 30000/10 = 3000, and log2(3000) = [11...7] = 12. The instructor completes the multi-level index design by computing how many key-pointer pairs fit in one block and how many blocks are needed to cover all 3,000 data blocks.

The video teaches primary indexing for an ordered file through a numerical example. Key concepts: blocking factor (records per data block), number of data blocks, index entry size (key + pointer), entries per index block, and multi-level index structure. The method: (1) BF = floor(B / R); (2) n = r / BF; (3) index entry size = key length + pointer length; (4) entries per index block = floor(B / entry size); (5) first-level index blocks = ceil(n / entries per block). The worked example yields BF = 10, n = 3,000, entry size = 15 B, entries per block = 68, and first-level index blocks = 45. The log2(3000) = 12 calculation appears alongside, possibly indicating pointer bit-width or a related bound. Diagrams show index blocks with 9 B keys and 6 B pointers linked to data blocks containing 30,000 records. Central ideas: primary index has one entry per data block; entries are ordered by key; multi-level structure reduces I/O. Minor details: the (1024 - 8) variant suggests block overhead may be subtracted in some formulations.

Loading lesson…