Short Tricks to Solve Questions Quickly

Duration: 11 min

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Module outline

  1. About the Course: About the Course
  2. Paper-1 & 2 | Basic Numeracy: Ratio and Proportion (Ratios), Divisibility Rules, Mixture and Alligation, Permutation and Combination, Logarithm, Number System, HCF LCM, Sequence and Series (Series), Speed Time and Distance, Percentage, Average, Mensuration and Geometry, Age Problems, Arithmetic, Statistics, Probability, Profit and Loss, Simple Interest and Compound Interest, Partnership, Speed Mathematics and Basic Mathematics, Algebra, Powers and Exponents (Surds and Indices), Time and Work, Pipe and Cistern, RSSB Specific Videos - Basic Numeracy
  3. Paper-1 & 2 | Data Interpretation: Data Interpretation
  4. Paper-1 & 2 | General Mental Ability: Mental Ability, RSSB Specific Videos - Mental Ability
  5. Paper-1 & 2 | Logical Reasoning and Analytical Ability: Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Data Sufficiency, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Syllogisms, Seating Arrangements, Blood Relations, Directions (Direction Test), Analytical Reasoning (Counting Figures Reasoning), Puzzle Solving (Puzzles), Calendar, Clock, Cubes & Dices, Venn Diagram, Analogy, Ranking, Order and Sequence, Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Data Arrangement, Logical Sequence Of Words, Crypt Arithmetic
  6. Paper-1 & 2 | Decision Making and Problem Solving: Selection Decision Table (Decision Making)
  7. Paper-1 | General Science: Physics, Biology, Chemistry, RSSB Specific Videos
  8. Paper-1 | General Awareness: State Wise GK, GK- Current Affairs
  9. Paper-2 | Fundamentals of Computer: Basics of COA, Number System, Floating Point Rep, Number Representation
  10. Paper - 2 | Digital Logic Systems: Digital Systems & Boolean Basics, Logic Gates & Hardware, Boolean Expression, Boolean Minimization, Combinational Circuit, Sequential Circuits
  11. Paper-2 | Operating Systems: Introduction to OS, Process Management, CPU Scheduling, Process Synchronization, Deadlock, Threads & Process Creation, Memory Management, Virtual Memory, Disc Scheduling, File Management, Linux OS, Distributed Systems
  12. Paper-2 | Database Management System: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, Relational Algebra, SQL, Relational Calculus, File Organization & Indexing, Transaction Management, Concurrency Control
  13. Paper-2 | Data Structures: Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing
  14. Paper-2 | C Programming: C Fundamentals, Control Flow, Functions, Arrays & Pointers, Storage Classes, Structures & Enums, DMA, Macros, Scoping & File Handling
  15. Paper 2 | Oops, C++, Java: Language Design, OOPS with C++, Java, .Net Programming, Java Fundamentals
  16. Paper 2 | Python: Introduction to Python, Tokens, Variables, Data Types, I/O, Operators & Expressions, Control Flow & Looping, Collections & Strings, Functions & Modules, File Handling & Data Analysis
  17. Paper 2 | Emerging Trends and AI: Emerging Tech Trends, Artificial Intelligence
  18. Paper-2 | Algorithms: Algorithm Analysis, Time Complexity Analysis, Sorting Algorithms, Greedy Algorithms, Advanced Algorithms
  19. Paper 2 | Data Communication and Network Security: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics, Network Security, Ethical Hacking
  20. Paper-2 I Software Engineering: Fundamentals of Software Engineering, Software Requirements and Quality Assurance, Software Design, Estimation and Metrics, Software Testing, Software Maintenance and Configuration Management
  21. Paper-2 | Computer Organization and Architecture: Cache Memory Organization, Input Output Organisation, Instr Formats & Modes, Control Unit Design, Register Transfer and Microoperations
  22. Paper-2 | Web Development: JavaScript-Basics, HTML Basics, CSS, XML
  23. Pedagogy: Child Development, Concept of Pedagogy, Psychology, Theories, Inclusive Education, Experiential Pedagogy, Curriculum Framework & Reforms, National Education Policy (NEP) 2020
  24. Live Sessions: RSSB Live Sessions
  25. RSSB Paper 1 - Full Mock Tests:
  26. RSSB Paper 2 - Full Mock Tests:
  27. SCI Previous Year Papers:
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

This educational video is a tutorial on calculating selling price given cost price and profit or loss percentage, presented by an instructor from Knowledge Gate. The video begins with a problem involving a packet of Vimal Pan Masala, where the cost price is Rs. 560 and the profit is 12.5%, and the instructor demonstrates three distinct methods to find the selling price. The first method uses the formula SP = CP(100 + P)/100. The second method, the Percentage Method, calculates the profit amount as a percentage of the cost price and adds it to the CP. The third method, the Ratio Method, converts the profit percentage into a ratio of profit to cost price, then uses the total parts to find the selling price. The video then transitions to a second problem about a cycle bought for Rs. 1400 and sold at a 15% loss, applying the same three methods to find the selling price. The instructor uses a green chalkboard to write out the formulas and calculations, and the video concludes with a 'Thanks for Watching' screen.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The video opens with a title card showing a 3D figure on a balance scale with 'PROFIT' and 'LOSS' on either side, setting the theme of the lesson. The main content begins with a problem displayed on a green screen: 'Q1: The cost price of a packet of Vimal Pan Masala is Rs. 560 and sold at a profit of 12.5 %. Find the selling price?'. The instructor, visible in a small window, introduces the problem. The screen also shows a meme with Deepika Padukone and a man, and text indicating the question was asked in the TCS EXAM (2012). The instructor states that the video will cover three methods to solve such problems.

  2. 2:00 – 5:00 02:00-05:00

    The instructor begins the first method, labeled 'Method 1 (Formula)'. He writes the formula SP = CP(100 + P)/100 on the green board. He substitutes the given values: CP = 560 and P = 12.5. The calculation proceeds as SP = 560(100 + 12.5)/100, which simplifies to SP = 560(112.5)/100. He then performs the multiplication and division, showing that 560 * 112.5 = 63000, and 63000 / 100 = 630. The final answer is SP = Rs. 630. The instructor explains that this is the most direct formula-based approach.

  3. 5:00 – 10:00 05:00-10:00

    The instructor introduces the second method, 'Method 2 (Percentage Method)'. He explains that the profit is 12.5% of the cost price. He writes the formula SP = CP + P, where P = (12.5/100) * CP. He calculates the profit amount: (12.5/100) * 560 = 70. He then adds this profit to the cost price: SP = 560 + 70 = 630. The result is the same as the first method. He then moves to the third method, 'Method 3 (Ratio Method)'. He converts the profit percentage 12.5% into a fraction: 12.5/100 = 1/8. This means the profit is 1 part and the cost price is 8 parts. The selling price is the sum of these parts, so SP = 1 + 8 = 9 parts. He sets up a proportion: 8 parts = 560, so 1 part = 70. Therefore, 9 parts = 9 * 70 = 630. All three methods yield the same selling price of Rs. 630.

  4. 10:00 – 11:25 10:00-11:25

    The video transitions to a new problem, Q2: 'A man buys a cycle of Rs. 1400 and sells it at a loss of 15 %. What is the selling price of the cycle?'. The instructor applies the same three methods. For Method 1, he uses the formula SP = CP(100 - L)/100, where L is the loss percentage. Substituting the values, SP = 1400(100 - 15)/100 = 1400(85)/100 = 1190. For Method 2, he calculates the loss amount as 15% of 1400, which is 210, and subtracts it from the CP: SP = 1400 - 210 = 1190. For Method 3, he converts 15% to a fraction, 15/100 = 3/20. This means the loss is 3 parts and the cost price is 20 parts. The selling price is 20 - 3 = 17 parts. He sets up the proportion: 20 parts = 1400, so 1 part = 70. Therefore, 17 parts = 17 * 70 = 1190. The video ends with a 'THANKS FOR WATCHING' screen.

The video provides a comprehensive, multi-method approach to solving profit and loss problems. It systematically demonstrates three distinct techniques—Formula, Percentage, and Ratio—on two different problems, one with a profit and one with a loss. The core concept is that the selling price can be found by either adding the profit to the cost price or subtracting the loss from it. The video emphasizes that while the methods differ in their approach, they all lead to the same correct answer, reinforcing the underlying mathematical principles. This structured presentation helps students understand the flexibility of problem-solving and choose the method that is most intuitive for them.

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