SubNetting In CIDR
Duration: 4 min
This video lesson is available to enrolled students.
Inside: a video lesson and guided study material.
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- About the Course: About the Course
- Paper-1 & 2 | Basic Numeracy: अनुपात और समानुपात / Ratio and Proportion, Divisibility Rules, मिश्रण और एलिगेशन / Mixture and Alligation, Permutation and Combination, Logarithm, संख्या पद्धति / Number System, महत्तम समापवर्तक और लघुत्तम समापवर्त्य / HCF and LCM, Sequence and Series (Series), समय, चाल और दूरी / Time, Speed and Distance, प्रतिशत / Percentage, औसत / Average, घन क्षेत्रमिति / Solid Mensuration, Age Problems, Arithmetic, Statistics, Probability, लाभ, हानि और बट्टा / Profit, Loss and Discount, साधारण और चक्रवृद्धि ब्याज / Simple and Compound Interest, Partnership, Speed Mathematics and Basic Mathematics, Algebra, सरलीकरण, घातांक और करणी / Simplification, Indices and Surds, समय और कार्य / Time and Work, Pipe and Cistern, RSSB Specific Videos - Basic Numeracy, समुच्चय, संबंध, फलन और विविक्त गणित / Sets, Relations, Functions and Discrete Mathematics, संख्या पद्धति और संख्या सिद्धांत / Number Systems and Number Theory, निर्देशांक ज्यामिति, सदिश और त्रिविमीय ज्यामिति / Coordinate Geometry, Vectors and 3D Geometry, बहुपद, समीकरण और सम्मिश्र संख्याएँ / Polynomials, Equations and Complex Numbers
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- Emerging Trends and AI: Emerging Tech Trends, कंप्यूटर के मूल सिद्धांत / Computer Fundamentals, व्यापार, विपणन एवं उपभोक्ता संरक्षण / Trade, Marketing and Consumer Protection
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AI summary & chapters
AI Summary
An AI-generated summary of this video lecture.
This lecture demonstrates subnetting in CIDR by dividing the network 20.30.40.10/25 into two subnets. The instructor writes the network address, converts it to binary, and identifies the host bits available after the /25 prefix. By borrowing one additional bit from the host portion, the original network is split into two /26 subnets. The first subnet is shown as 20.30.40.0/26, while the second is indicated as 20.30.40.128/26, with binary rows and circled bits used to show the subnet bit transition. The board also displays power-of-two values, including 2^7 = 128 and 2^6 = 64, supporting the calculation of address ranges. The final visible evidence shows a circle divided into two halves representing the two resulting subnets, with tally marks or host-bit placeholders along the bottom. The lesson focuses on practical CIDR subnet division, binary representation, and deriving new network addresses from a single borrowed bit.
Chapters
0:00 – 2:00 00:00-02:00
The instructor introduces the problem under the header “Subnetting in CIDR,” asking students to divide the network having IP address 20.30.40.10/25 into two subnets. The network address is written on the board, and a large circle is drawn in the center as a visual aid. The instructor then begins converting parts of the address into binary, writing “0000” after an underlined address and placing “20.30.40” on the right side of the board, setting up the binary analysis needed for subnetting.
2:00 – 4:17 02:00-04:17
The instructor writes binary representations of the address on both sides, circling specific bits to show which host bit is borrowed for subnetting. The resulting network addresses are derived, with “20.30.40.0” written for the first subnet and a second address beginning with “20.30.40.1” shown for the other half. The central circle is split into two halves, labeled “20.30.40.0/26” on the left and a second /26 address on the right, later visible as “20.30.40.128.” The board also shows “2^7 = 128” and “2^6 = 64,” indicating the size calculations used to determine subnet boundaries.
The core teaching point is how a /25 network can be divided into two smaller subnets by borrowing one host bit, producing two /26 networks. The instructor uses binary notation to make the subnet bit explicit: after the original 25 network bits, one additional bit is taken from the host portion to create two possible values. This yields 20.30.40.0/26 and 20.30.40.128/26, with the value 128 coming from the binary weight of the borrowed bit. The circle diagram visually separates the original network into two halves, reinforcing that one subnet uses a 0 in the borrowed bit and the other uses a 1. The displayed powers of two, especially 2^7 = 128 and 2^6 = 64, connect the binary bit position to address range sizes. For exam revision, students should remember that increasing the prefix length by one bit doubles the number of subnets and halves the host space, while the new network addresses are found by setting borrowed subnet bits to 0 or 1 and host bits to 0.